I'm confused about this physics question
A ball is thrown horizontally from the top of a building.
The ball is thrown with a horizontal speed of 8.2 m s-1. At point P on the trajectory, the ball is a
distance x from the building and is moving at an angle of 60o
to the horizontal. Air resistance is
negligible. For the ball at point P:
i) show that the vertical component of its velocity is 14.2 m s-1
Okay so using trigonometry I did Sin(60)*8.2 to find the vertical component but my answer was 7.1 which is exactly half of the answer I need so I would assume I need to multiply by 2 but I'm not sure why or if I've just done it wrong
Could someone help thanks
The ball is thrown with a horizontal speed of 8.2 m s-1. At point P on the trajectory, the ball is a
distance x from the building and is moving at an angle of 60o
to the horizontal. Air resistance is
negligible. For the ball at point P:
i) show that the vertical component of its velocity is 14.2 m s-1
Okay so using trigonometry I did Sin(60)*8.2 to find the vertical component but my answer was 7.1 which is exactly half of the answer I need so I would assume I need to multiply by 2 but I'm not sure why or if I've just done it wrong
Could someone help thanks
Original post by Connor09
Draw a diagram to see what’s going on.
What made you use sin?
What made you use sin?
Sorry there was a diagram with the question I thought it uploaded here it is
Original post by Connor09
Okay great, now what made you use sin? You’re right in using trigonometry.
I need the opposite side and I have the hypotenuse so O=sin(x) *H
Original post by Connor09
Do you have the hypotenuse? You are given the horizontal.
Oooohhhh *facepalms* yeah no I don't I have the adjacent so I shouldve used tan
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