I'm a little confused about this question I'll show what I've got so far please point out if I'm wrong but I did
I) 0.5*600*(9.5/cos(30))^2 = 36100J ii) 600*9.81*4.1 = 24132.6J iii) this is where I'm confused I understand work done is force*distance so the distance I worked out to be 4.1/sin(30) =8.2m Then I need to work out the force due to friction but idk how is it 600*9.81*sin (30)or am I completely wrong Also the last question I do think know where to start
for i it says kinetic energy travelling towards the slope, you have calculated kinetic energy when on the slope
Actually you wouldn't do that calculation for KE on the slope because KE isn't a vector quantity. 1kg moving at 1m/s has the same KE as 1kg moving at -1m/s (or moving at 1m/s in any other direction)
note 0.5*600*9.5^2 = 27075 J the KE the trolley had on the level where did the extra 9025 J of KE suddenly come from when it started going up the slope?