y intersection is given by substituting x=0 into the eq.
As for the asymptote, note that there exists a sequence of transformations from ex and e2x+1 which doesn't have anything to do with the y-axis/direction, so the horizontal asymptote y=0 is unchanged. Alternative, observe what value this function approaches as x→−∞
To find the y-intercept, you simply plug x=0 into the function. And the intercept can be found by taking the asymptote of ex and adding to it the constant by which the new function has been translated up
y intersection is given by substituting x=0 into the eq.
As for the asymptote, note that there exists a sequence of transformations from ex and e2x+1 which doesn't have anything to do with the y-axis/direction, so the horizontal asymptote y=0 is unchanged. Alternative, observe what value this function approaches as x→−∞
To find the y-intercept, you simply plug x=0 into the function. And the intercept can be found by taking the asymptote of ex and adding to it the constant by which the new function has been translated up
can u tell me why e^2x intersects at y=2 plz? thank you