Original post by DQd
I have this equation:
Where u is a function, ct and cnt are variables and ubar a constant.
And need to find:
How would I start this?
Where u is a function, ct and cnt are variables and ubar a constant.
And need to find:
Attachment not found
How would I start this?
Just differentiate through by . This means that for the first term you must use the chain rule.
Original post by RDKGames
Just differentiate through by . This means that for the first term you must use the chain rule.
Thanks, got the answer.
Didn't think to split the first term.
As an aside, is it incorrect to say the first term
Original post by DQd
Thanks, got the answer.
Didn't think to split the first term.
As an aside, is it incorrect to say the first term is equal to 0 because there is no cnt in 0.5u(ct)?
Didn't think to split the first term.
As an aside, is it incorrect to say the first term is equal to 0 because there is no cnt in 0.5u(ct)?
Yes that's incorrect.
If you were to differentiate w.r.t , you'd say and not .
If was constant, then yes the derivative would make it 0
Original post by Notnek
I don't like the look of that equation...
What's wrong with it?
Original post by RDKGames
Yes that's incorrect.
If you were to differentiate w.r.t , you'd say and not .
If was constant, then yes the derivative would make it 0
If you were to differentiate w.r.t , you'd say and not .
If was constant, then yes the derivative would make it 0
Got it.
The solutions only have one step:
Is there any slightly different method to solve this or do you think it's just the method you stated but multiplied by dcnt
Original post by DQd
Got it.
The solutions only have one step:
Is there any slightly different method to solve this or do you think it's just the method you stated but multiplied by dcnt
The solutions only have one step:
Is there any slightly different method to solve this or do you think it's just the method you stated but multiplied by dcnt
Yes, indeed it is the exact same method as I said but they made an extra step afterwards of multiplying through by
Original post by RDKGames
What's wrong with it?
Ignore me.
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