HELP!!!

How would you find the turning point of a quadratic graph when you are only given the y intercept(0,-10) and the coordinate of one intersection on the x axis (5,0)? Any help would be really appreciated.

Reply 1

Mehru1214

Do you know the exact question? Like, if you can assume a=1 in ax^2 + bx + c ?

Reply 2

gdunne42

Original post by Mehru1214

Do you know the exact question? Like, if you can assume a=1 in ax^2 + bx + c ?

Yes in the actual question the coefficient of x^2 is 1

Reply 3

Mehru1214

Original post by gdunne42

Yes in the actual question the coefficient of x^2 is 1

Ok, gimme a few mins, I can figure it out!

Reply 4

Dan_Jenkins

Original post by Mehru1214

Ok, gimme a few mins, I can figure it out!

I know the answer from the mark scheme I think it's 1.5 just don't have any idea how to do it

Reply 5

Mehru1214

Original post by Dan_Jenkins

I know the answer from the mark scheme I think it's 1.5 just don't have any idea how to do it

Ok, so here's my way of doing it, using what I was taught. I'm a grade 9 student, so I know it's right, just may be a little hard to understand. Hopefull you can read it!

(edited 6 years ago)

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Reply 6

Dan_Jenkins

Original post by Mehru1214

Ok, so here's my way of doing it, using what I was taught. I'm a grade 9 student, so I know it's right, just may be a littl hard to understand. Hopefull you can read it!