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Simplifying a Logs

log(210)−13log(0.8)−log(103)log(2\sqrt{10})-\frac{1}{3}log(0.8)-log(\frac{10}{3})

log(3105)−log(0.8)13log(\frac{3\sqrt{10}}{5})-log(0.8)^{\frac{1}{3}}

How can I simplify this further to get c+logdc + logd where c and d are rational numbers?
(edited 6 years ago)
Original post by joyoustele
log(210)−13log(0.8)−log(103)log(2\sqrt{10})-\frac{1}{3}log(0.8)-log(\frac{10}{3})

log(3105)−log(0.8)13log(\frac{3\sqrt{10}}{5})-log(0.8)^{\frac{1}{3}}

How can I simplify this further to get c+logdc + logd where c and d are rational numbers?


Separate the first log. Also note that 0.8=8/10

You basically want to separate into log(10)’s and something else essentially
(edited 6 years ago)
Reply 2
Avatar for joyoustele
joyoustele
OP
19
Original post by RDKGames
Separate the first log. Also note that 0.8=8/10

You basically want to separate into log(10)’s and something else essentially


Still stuck...

log(310)−log(5)−log(2)−log1013log(3\sqrt{10})-log(5)-log(2)-log10^{\frac{1}{3}}

log(310)−log(5)−log(2)−13log(3\sqrt{10})-log(5)-log(2)-\frac{1}{3} ?
Original post by joyoustele
Still stuck...

log(310)−log(5)−log(2)−log1013log(3\sqrt{10})-log(5)-log(2)-log10^{\frac{1}{3}}

log(310)−log(5)−log(2)−13log(3\sqrt{10})-log(5)-log(2)-\frac{1}{3} ?


Split the first log, you still got a 10 available for cancelling with a log.
Reply 4
Avatar for joyoustele
joyoustele
OP
19
Original post by RDKGames
Split the first log, you still got a 10 available for cancelling with a log.


Yh, Thanks I realised I just had to keep going. Thats a pretty weird question... Thanks for the help

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