I tried it in another thread been trying to find out what to do for an hour and still at the same point, just want someone to show workings so i can see what i'm doing wrong

Reply 4

Plagioclase

Original post by ᒍack

I tried it in another thread been trying to find out what to do for an hour and still at the same point, just want someone to show workings so i can see what i'm doing wrong

How would you differentiate

x^{\frac{3}{2}}

? It's just that, but multiplied by

\sqrt{2}

Reply 5

ruhplus

before any help, perhaps share your thought process when looking at the question. What is it exactly that you are having a hard time with.

Reply 6

RedGiant

Multiply the x coefficient (root 2) by the exponent, and simply decrease the exponent by 1.

(edited 6 years ago)

Reply 7

Muttley79

Original post by ᒍack

I tried it in another thread been trying to find out what to do for an hour and still at the same point, just want someone to show workings so i can see what i'm doing wrong

What is the rule for differentiating ax^n?

Reply 8

ᒍack

Original post by RedGiant

Multiply the x coefficient (root 2) by the exponent, and simply decrease the exponent by 1. Root 2 is simply a constant.

Thank you

Reply 9

ᒍack

Original post by Muttley79

What is the rule for differentiating ax^n?

anx^n-1

Reply 10

ᒍack

Oops, I meant to put

\ 2^{-1/2} * x^{3/2}

Reply 11

ruhplus

again just take the 2^-1/2 as a constant and multiply it by the derivative of x^3/2 you can then do some tidying up of the answer if you want I don't know if im supposed to send a pic of the full solution or not

Reply 12

ᒍack

Original post by ruhplus

I ended up doing

\ 1/2^{-1/2} * 3/2

then doing

\ x^{1/2} * 3

then cleaning it up to give

\ 3/2*x^{1/2}/2^{1/2}

(edited 6 years ago)

Reply 13

username3556062

Rather simple. Root of 2 is a constant so the basic power rule is enough.

Reply 14

ruhplus

Original post by ᒍack

I ended up doing

\ 1/2^{-1/2} * 3/2

then doing

\ x^{1/2} * 3

then cleaning it up to give

\ 3/2*x^{1/2}/2^{1/2}

right so, firstly I think you made a typo as its

\ 1/2^{1/2}

not a negative 1/2, as having 1 over a negative power makes a positive one. Also, why did you do

\ x^{1/2} * 3

(edited 6 years ago)

Reply 15

ᒍack

Original post by ruhplus

right so, firstly I think you made a typo as its

\ 1/2^{1/2}

not a negative 1/2, as having 1 over a negative power makes a positive one. Also, why did you do

\ x^{1/2} * 3

Yeah it's meant to be ^-1/2

Reply 16

ᒍack

Original post by ruhplus

right so, firstly I think you made a typo as its

\ 1/2^{1/2}

not a negative 1/2, as having 1 over a negative power makes a positive one. Also, why did you do

\ x^{1/2} * 3

Ahhh.. i see what people mean now.. I didn't know I could just keep the constant and take the derivative of the rest of the term then multiply... my book didn't even mention it... ughh.... tgwerhbwtehiuoqwerhgfw3hrgbw4rhbw45thwrthw45thw4thw4thmndtyj erythje6t4r4r4r4r4r4rytrey

Thanks everyone..

Reply 17

ruhplus

Original post by ᒍack

Yeah it's meant to be ^-1/2

yeah but

\ 1/2^{1/2}

is the same as

\ 2^{-1/2}

so I'm just saying that you kind of did a maths equivalent of a double negative. Your answer is almost right but as I implied in the last message you shouldn't have multiplied by just a 3.