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C3- stuck on a question

Curve C has equation y=e2x+x2+4x+1y=e^{2x}+x^2+4x+1

Show that the x-coordinate of any stationary point of C satisfies the equation.x=2e2x x=-2-e^2x

I differentiated the equation, then equated it to 0 and got
2e2x+2x+4=02e^{2x}+2x+4=0
I assume I have to solve for x, but I get stuck at
e2x+x=e42e^{2x}+x=\frac{e-4}{2}

Could anyone help?
Reply 1
Original post by joyoustele
Curve C has equation y=e2x+x2+4x+1y=e^{2x}+x^2+4x+1

Show that the x-coordinate of any stationary point of C satisfies the equation.x=2e2x x=-2-e^2x

I differentiated the equation, then equated it to 0 and got
2e2x+2x+4=02e^{2x}+2x+4=0
I assume I have to solve for x, but I get stuck at
e2x+x=e42e^{2x}+x=\frac{e-4}{2}

Could anyone help?

I'm not sure how you ended up with that. You don't need to "solve for x" here, instead just rearrange your equation to get to their one. So you have

2e2x+2x+4=02e^{2x}+2x+4=0

and you need

x=2e2xx=-2-e^{2x}

Start by moving the 2e2x2e^{2x} and the 44 to the other side.
Reply 2
Original post by Notnek
I'm not sure how you ended up with that. You don't need to "solve for x" here, instead just rearrange your equation to get to their one. So you have

2e2x+2x+4=02e^{2x}+2x+4=0

and you need

x=2e2xx=-2-e^{2x}

Start by moving the 2e2x2e^{2x} and the 44 to the other side.


Oh, I just didnt understand the Question. So if a question was to say show that something x satisfies [equation], do I just always rearrange to make their equation?
Original post by joyoustele
Oh, I just didnt understand the Question. So if a question was to say show that something x satisfies [equation], do I just always rearrange to make their equation?


Yes.

What else could you do?
Original post by joyoustele
Curve C has equation y=e2x+x2+4x+1y=e^{2x}+x^2+4x+1

Show that the x-coordinate of any stationary point of C satisfies the equation.x=2e2x x=-2-e^2x

I differentiated the equation, then equated it to 0 and got
2e2x+2x+4=02e^{2x}+2x+4=0
I assume I have to solve for x, but I get stuck at
e2x+x=e42e^{2x}+x=\frac{e-4}{2}

Could anyone help?


dy/dx= 2e^2x+ 2x+ 2
at stationary point dy/dx=0 therefore
2e^2x+2x+4=0
e^2x+x+2=0
x= -2-e^2x
is that right?
Reply 5
Original post by joyoustele
Oh, I just didnt understand the Question. So if a question was to say show that something x satisfies [equation], do I just always rearrange to make their equation?

Isn't that clear from the question? Why would you try to make a different equation instead of the one they give you?
Reply 6
Original post by Notnek
Isn't that clear from the question? Why would you try to make a different equation instead of the one they give you?


Argh nevermind...Im a noob

Thanks for your help
Reply 7
Original post by etothepiiplusone
Yes.

What else could you do?


Ermm... Not do what they asked you to do

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