Can you show me the numbers we are adding up? Also isn't Enthalpy of formation of barium chloride, the enthalpy change we need to calculate temperature?
Can you show me the numbers we are adding up? Also isn't Enthalpy of formation of barium chloride, the enthalpy change we need to calculate temperature?
Calculate a value for the electron affinity of chlorine.
Data
Enthalpy of atomisation of barium +180 kJ mol–1 Enthalpy of atomisation of chlorine +122 kJ mol–1 Enthalpy of formation of barium chloride –859 kJ mol–1 First ionisation enthalpy of barium +503 kJ mol–1 Second ionisation enthalpy of barium +965 kJ mol–1 Lattice formation enthalpy of barium chloride –2056 kJ mol–1
Ba(s) + Cl2(g) --> BaCl2(s)............. -859 kJ
Ba(s) --> Ba(g)......................... +180kJ
Cl2(g) --> 2Cl(g)....................... +244kJ
Ba(g) --> Ba2+(g)..................... +1468 kJ
2Cl(g) + 2e --> 2Cl-(g)................. 2 x electron affinity
Ba2+(g) + 2Cl-(g) --> BaCl2(s)......... -2056 kJ
Calculation:
180 + 244 + 1468 + 2EA -2056 = -859
gather and rearrange
2EA = -695
Electron affinity of chlorine = -347.5 kJ mol-1
(b) The equation given is the reverse of the formation enthalpy = +859 kJ