mansnothot
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#1
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#1
i dont get how to solve this? thanks
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exhaustedstudent
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#2
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Is it from a test paper? If so do you know which one?
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mansnothot
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#3
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(Original post by exhaustedstudent)
Is it from a test paper? If so do you know which one?
yes i do why?
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Tasnim:)
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#4
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think of it as this alcohol + NaBr +acid catalyst ---> Haloalkane ???
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rose.a
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#5
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16+1+12+2+12+16+16+1
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mansnothot
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#6
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(Original post by Tasnim:))
think of it as this alcohol + NaBr +acid catalyst ---> Haloalkane ???
so the OH group substitutes with the Br in NaBr?
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Tasnim:)
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(Original post by Tasnim:))
think of it as this alcohol + NaBr +acid catalyst ---> Haloalkane ???
then find the molar mass of the haloalkane produced if that makes sense?

Basically the carboxylic acid end doesnt change, only the OH group does
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Tasnim:)
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#8
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(Original post by mansnothot)
so the OH group substitutes with the Br in NaBr?
yep
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exhaustedstudent
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#9
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(Original post by mansnothot)
yes i do why?
was going to look it up, because it was frustrating me that I couldn’t do it haha
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