The Student Room Group

How to find the limit of a converging sequence??

Un = 3n^2 + 1 all over n^2... Can someone help me on how to find the limit to this converging sequence?
Reply 1
Long division first, then let n--> infinity to get the limit
Original post by apaul322
Un = 3n^2 + 1 all over n^2... Can someone help me on how to find the limit to this converging sequence?


Well you want to find the limit of 3n2+1n23+1n2\frac{3n^2+1}{n^2} \equiv 3 + \frac{1}{n^2}
Let's think about what happens as n approaches infinity: that is, n becomes RIDICULOUSLY large.
3 will stay as 3
1/n^2? Well 1/(a very big number) will limit to 0
So it converges to 3 + 0 = 3.
Reply 3
Original post by 3pointonefour
Well you want to find the limit of 3n2+1n23+1n2\frac{3n^2+1}{n^2} \equiv 3 + \frac{1}{n^2}
Let's think about what happens as n approaches infinity: that is, n becomes RIDICULOUSLY large.
3 will stay as 3
1/n^2? Well 1/(a very big number) will limit to 0
So it converges to 3 + 0 = 3.


Thanks soo muchh helped me a lott
Original post by apaul322
Thanks soo muchh helped me a lott


No problem :smile:
What level of maths are you studying at, just out of interest?
Reply 5
Original post by 3pointonefour
No problem :smile:
What level of maths are you studying at, just out of interest?


i have my Core Maths 2 exam this weednesday and im doing my A levels at the moment.. What do u mean by level?
Original post by apaul322
i have my Core Maths 2 exam this weednesday and im doing my A levels at the moment.. What do u mean by level?


I meant whether you were studying at AS, A2 etc. Well good luck for your exam!
Reply 7
Original post by 3pointonefour
I meant whether you were studying at AS, A2 etc. Well good luck for your exam!


im doing my A2 atm :smile:

Quick Reply

Latest