MAT Prep Thread 2018

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Thanks a lot. I will be more involved with this thread from tomorrow. What is an OP by the way?

Original post :h:

the STEP thread has a very extensive first post which is used every year and elaborates a lot more on STEP than this one does on MAT. It would be great if you and/or other MAT candidates/people who know about MAT could make an OP which is just as informative as the STEP one (I'd help but I'm a modern languages applicant who knows pretty much nothing about MAT :lol:

Reply 21

r_gup

Original post by Sonechka

Original post :h:

Thanks. How can I add/edit the first post?

Reply 22

Quirky Object

Original post by r_gup

Thanks. How can I add/edit the first post?

At the bottom of the post and to the left of the orange button which says "reply", there should be an edit button.

Reply 23

r_gup

Original post by Sonechka

At the bottom of the post and to the left of the orange button which says "reply", there should be an edit button.

Thanks. Found it.

Reply 24

r_gup

I am unable to upload the past papers in the first post. TSR's websit keeps showing 'Service Unavailable'. What should I do?

Reply 25

r_gup

Found this question in the STEP thread. I feel it is relevant to the MAT.

Original post by thotproduct

??
Please explain.

Reply 28

thotproduct

Original post by r_gup

??
Please explain.

Fairly self explanatory.

I'm doing the question now, chat more when I've done.

Reply 29

Lemur14

Volunteer Section Leader

Original post by r_gup

I am unable to upload the past papers in the first post. TSR's websit keeps showing 'Service Unavailable'. What should I do?

Attachments often cause problems. Just link the MAT website with them all on :smile:

That OP is generally rather out of date given it's talking about the old specification MAT, old spec maths etc. I've been doing a fair bit of research into what's changed and could update the OP if you're happy with that?

Posted from TSR Mobile

Reply 30

r_gup

Original post by Lemur14

Attachments often cause problems. Just link the MAT website with them all on :smile:

Yes, please.

Reply 31

r_gup

What should be the answer? Boris?

Reply 32

r_gup

What should be the answer?
Either (iii) and (iv){for a=c and b=d} or (i) and (iv) { for a=b and c=d}?

Reply 33

s.xw

38178649-EFAF-46A1-8034-98CE42FB0670.jpg.jpeg

Could someone please explain what this solution means? What does it mean by the second equality? It’s not clear to me how they get from sinx < x < tanx to the required result. Thanks.

Reply 34

r_gup

Original post by s.xw

Could someone please explain what this solution means? What does it mean by the second equality? It’s not clear to me how they get from sinx < x < tanx to the required result. Thanks.

Can you please upload the entire image or the year of the paper?

Reply 35

r_gup

Original post by r_gup

Can you please upload the entire image or the year of the paper?

Sorry , found it . MAT 2010 Question 3.

Reply 36

s.xw

Original post by r_gup

Can you please upload the entire image or the year of the paper?

2010 Q3 (i) requires you to derive a given result from a diagram. The rest of the question uses this result and I was able to get most of it, but I just don’t get what their solution to (i) is trying to say.

Reply 37

r_gup

Original post by s.xw

So , Area

\Delta

OAC =

\frac{1}{2}

sin(x)
Area Sector OAC =

\frac{1}{2}

x
Area

\Delta

OAB =

\frac{1}{2}

tan(x)

As Area

\Delta

OAC< Area Sector OAC<Area

\Delta

OAB,

\frac{1}{2}

sin(x)<

\frac{1}{2}

\frac{1}{2}

tan(x)

so sin(x)<x<tan(x)

Now multiplying with cos(x),

\frac{sin(2x)}{2}

<xcos(x)<sin(x)
as tan(x) =

\frac{sin(x)}{cos(x)}

, hence cos(x) will be cancelled out.
Using sin(x)> xcos(x) ,(from the above inequality)
x>sin(x)>xcos(x)

(edited 5 years ago)

Reply 38

s.xw

Original post by r_gup

What should be the answer?
Either (iii) and (iv){for a=c and b=d} or (i) and (iv) { for a=b and c=d}?

This is a guess. But they imply that
if a-d = c-b, then
ad ≠ bc.
Therefore c > a, b > d or c < a, b < d. This contradicts (i). Therefore (d) is the answer. As I say, complete guess and probably wrong! I’ve just started looking at MAT papers a few days ago.