AQA GCSE Further Maths 2018 unofficial mark scheme paper 1

johnthebaptist27

What did you guys get? Let's make an unofficial mark scheme

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Reply 1

Neccipp

For the 6 mark simultaneous equation

X was either 1/3 or -2
Y was either 6 or -1

Reply 2

Jakazen

Original post by johnthebaptist27

What did you guys get? Let's make an unofficial mark scheme

(x-2)(X+5)^2
Y=3/5x+25
4√3 for the last one
Solutions for simultaneous was (1/3, 6), (-2,-1) I think
K was 17
2x^2+16x+13 was 2(x-4)^2 -19
I think matrices was r1 c1 (4), R1 c2 (16), forgot R2 c1 but R2 c2 was 17
The first one I think was 3x^2 + x^3 I don't remember properly
-2 -7 was a and b respectively for the second one I think or it was for the coordinates of P when another line was parallel to the line tangent to the curve
(X+2)^2+(y-5)^2=25 given (-2,5)
48 one of them
Question with P and Q: x was 35

(edited 5 years ago)

Reply 3

Flyn_Higginson

20. I'm pretty sure that I got 4 root 3.
I got k as 17 for the quadratic expansion question.

Reply 4

Flyn_Higginson

Original post by Jakazen

(x-2)(X+5)^2
Y=3/5x+25
4√3 for the last one

Yeah same here
The first one was 3x^5 +x^3 (because it was (x^6)/2 +(x^4)/4) I think
And I'm pretty sure that R2 C1 was -8

(edited 5 years ago)

Reply 5

johnthebaptist27

For the line draw one I drew y = 2-x for answers of 3.6 and 0.6.

Reply 6

johnthebaptist27

Original post by Jakazen

(x-2)(X+5)^2
Y=3/5x+25
4√3 for the last one

same here

Reply 7

LottieLouLou

Original post by johnthebaptist27

For the line draw one I drew y = 2-x for answers of 3.6 and 0.6.

How did you work that one out? I got really stuck and put some random working down in the hope I might get a method mark (unlikely lol)

Reply 8

13dsaivaines

Original post by johnthebaptist27

For the line draw one I drew y = 2-x for answers of 3.6 and 0.6.

Omg I was so unsure on that and wasn't really sure what I was doing. Do you think that was right?

I also got that btw

Reply 9

username3723410

Original post by johnthebaptist27

For the line draw one I drew y = 2-x for answers of 3.6 and 0.6.

i got 3.4 and 0.6

Reply 10

johnthebaptist27

Original post by LottieLouLou

How did you work that one out? I got really stuck and put some random working down in the hope I might get a method mark (unlikely lol)

Well you were given a graph of 3x-x^2 and asked to solve x^2-4x+2, so if you add the two together, you get x^2 - x^2 +3x-4x + 2 = 2-x. THen draw this line on the graph and circle where 3x-x^2 and 2-x intersect

Reply 11

johnthebaptist27

Original post by 13dsaivaines

Omg I was so unsure on that and wasn't really sure what I was doing. Do you think that was right?

I also got that btw

Yh i am pretty sure because I checked in the exam and if you get the graph of x^2 -4x + 2 and complete the square, you get (x-2)^2 -2 = 0, hence x = 2+-sqrt(2), and i took the root of 2 to be 1.4 (remeber it as this), which gives 0.6 and 3.4

Reply 12

diamantes

Original post by Jakazen

(x-2)(X+5)^2
Y=3/5x+25
4√3 for the last one
Solutions for simultaneous was (-1/3, -6), (2,1) I think
K was 17
2x^2+16x+13 was 2(x-4)^2 -19
I think matrices was r1 c1 (4), R1 c2 (16), forgot R2 c1 but R2 c2 was 17
The first one I think was 3x^2 + x^3
-2 -7 was a and b respectively for the second one I think or it was for the coordinates of P when another line was parallel to the line tangent to the curve
(X+2)^2+(y-5)^2=25 given (-2,5)

I think I got 3x^5+x^3 for the first one and for the simultaneous I got 1/3 and 6, & -1 and -2

Reply 13

johnthebaptist27

Original post by somebrick

i got 3.4 and 0.6

yeah thats what I got i remembered incorrectly :biggrin:

Reply 14

13dsaivaines

Original post by johnthebaptist27

Yeah I did that as well and solved it using the quadratic formula but thought the root of 2 was 1.8 lol

Reply 15

Zain333

Original post by Flyn_Higginson

Yeah same here

What was the question for
Y = 3/5x +25

Reply 16

21Major

• The question where you had to work out the coordinates of point P on the curve with its tangent parallel to a given equation of a line:
(-0.70, -10.12).
• Last question (trig/surds): 4√3 (in the form a√b)
• Sketch question: obviously I can't show a sketch here but the coordinates, Max (-3, 13) & Min (1, 2⅓) and you roughly crossed the y-axis at (0,4).
• K = 17
• I didn't do quite well in the circle theorem but ig the main important angle (imo) that I worked out was 2x for one of the angles in the cyclic quadrilateral. I knew you ultimately needed to show two corresponding or alternate angles were equal to prove that the two lines were parallel, but I couldn't work the values
• equation for circle (tick box q): (x+1)²+(y-6)² = 25. I'm not quite sure about the actual coordinates of the centre given to us but it defo was a '+' in the 1st bracket, a '-' in the 2nd then 25 (5² = 25).