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A-level physics question help needed asap

A tennis ball is fired upwards at a speed of 60ms−1 from the top of a tall cliff. Where is it in relation to the starting point after 12.0s?
Original post by blank4567
A tennis ball is fired upwards at a speed of 60ms−1 from the top of a tall cliff. Where is it in relation to the starting point after 12.0s?


OK so what do we know ...
Taking upwards as positive
u = 60
a = -g
t = 12

Can you think of an equation that would help?
Original post by blank4567
A tennis ball is fired upwards at a speed of 60ms−1 from the top of a tall cliff. Where is it in relation to the starting point after 12.0s?


s=ut+at22s=ut+\frac{at^2}{2}
S=ut-1/2*g*t^2. you will get the displacement.
Reply 4
Original post by Alevelgoosegei
S=ut-1/2*g*t^2. you will get the displacement.

Thanks for the help i appreciate it!
Reply 5
good, sure you are the best we have to offer?
Reply 6
Original post by Vinny C
good, sure you are the best we have to offer?


Done that bit.
Reply 7
Original post by Alevelgoosegei
S=ut-1/2*g*t^2. you will get the displacement.

How did you get this equation??
Original post by Hash.m
How did you get this equation??

SUVAT
s = ut + 1/2 at^2
Reply 9
Original post by Muttley79
SUVAT
s = ut + 1/2 at^2

but the equation that worked has a minus instead of a plus?
Original post by Hash.m
but the equation that worked has a minus instead of a plus?

Yes because the object is thrown upwards and gravity is acting downwards ... read the whole thread.
is g -9.8? because when i plug that in, it says it’s not correct
answer =14m
Reply 13
How did you get that?

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