Capacitance in electric Fields

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Thread starter 2 years ago
#1
I'm covering electric fields in A2 physics, please may you answer this question 🙂?:

In the formula C = Q / V, please may you explain what V means - the potential difference of (or across) the sphere? 🧐😕
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2 years ago
#2
the potential at the surface of the sphere
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Thread starter 2 years ago
#3
(Original post by BobbJo)
the potential at the surface of the sphere
Isn't it potential difference? If so then would it be the potential difference across a diameter of the sphere? 🙂
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2 years ago
#4
(Original post by Freedom physics)
Isn't it potential difference? If so then would it be the potential difference across a diameter of the sphere? 🙂
no it is not potential difference at the the surface of the sphere

it is the potential at the surface of the sphere
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Thread starter 2 years ago
#5
(Original post by BobbJo)
no it is not potential difference at the the surface of the sphere

it is the potential at the surface of the sphere
So, for an electron at the surface of the sphere, V is the electric potential that the electron has? Like gravitational potential with the negative sign? 🙂
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2 years ago
#6
(Original post by Freedom physics)
So, for an electron at the surface of the sphere, V is the electric potential that the electron has? Like gravitational potential with the negative sign? 🙂
No the electric potential ENERGY that the electron has is -Ve (e is elementary charge)
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Thread starter 2 years ago
#7
(Original post by BobbJo)
No the electric potential ENERGY that the electron has is -Ve (e is elementary charge)
Thank you, I've made sense of the equation CV = Q but it only makes sense for me for one electron in the sphere, please may you help me make sense of it for the whole sphere? 🙂 the part I'm having trouble with is that, due to V being the work done to displace the sphere outside an electrical field affecting it, you can't move it out of the electrical field affecting it because there isn't one! 😄
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