Question 16, Multiple choice question which I don't really understand. I have the answer already but don't understand how to get there. I tried subbing the given variables into V=IR etc, which didn't really help.
Consider the first circuit Draw it Find that 4 IR = 3 V Second circuit drawn Now in reverse, the cell PD opposes the other two cells 2V - 1 = 4 iR (new I = i) Ratio of 1V / 3V = i/I = 1/3 = ratio of currents Hence 1/3
Consider the first circuit Draw it Find that 4 IR = 3 V Second circuit drawn Now in reverse, the cell PD opposes the other two cells 2V - 1 = 4 iR (new I = i) Ratio of 1V / 3V = i/I = 1/3 = ratio of currents Hence 1/3