The Student Room Group

Friction at inclined plane help

Could someone help me out with this please?
I tried solving it myself and my answer to N (normal force) was 217N but the real answer is 309N...
New Doc 2019-04-22 02.00.40_1-compressed.jpg.jpeg
Reply 1
How did you get 217? It seems too low even just including the box.
You also must include the normal component of P.
Original post by ddsizebra
Could someone help me out with this please?
I tried solving it myself and my answer to N (normal force) was 217N but the real answer is 309N...
New Doc 2019-04-22 02.00.40_1-compressed.jpg.jpeg
Reply 2
Original post by mqb2766
How did you get 217? It seems too low even just including the box.
You also must include the normal component of P.

I did....as x and y components since it's not strictly parallel to the plane
Original post by ddsizebra
I did....as x and y components since it's not strictly parallel to the plane


Post your full working then.
Reply 4
Original post by ghostwalker
Post your full working then.


New Doc 2019-04-22 08.19.56-compressed.jpg.jpeg
Reply 5
The normal force is perpendicular to the plane only.

Edit: 300 + 80;where both are resolved perpendicular to the plane.

Original post by ddsizebra
New Doc 2019-04-22 08.19.56-compressed.jpg.jpeg
(edited 5 years ago)
Reply 6
Original post by mqb2766
The normal force is perpendicular to the plane only.

Edit: 300 + 80;where both are resolved perpendicular to the plane.



but how about reaction? I applied them to a previous question to solve P which i had the correct answer to
Reply 7
I think yourey better trying to understand the mechanics, rather than trying to spot equations.
Both gravity and the pushing exert forces on the box. They need to be resolved along and perpendicular to the plane. These should be considered independently.
Original post by ddsizebra
but how about reaction? I applied them to a previous question to solve P which i had the correct answer to

Quick Reply

Latest