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Original post by AlexMurphy122
It had an anti node at the open end and a node at the closed end so ANAN, for the stationary waves


Yep, C.
Original post by zolfikar
I did AS physics last year and that **** was hard

Our school did that for mocks and general consensus is that this year's is a bit harder I think
Reply 62
oh what did people get for the steam multiple choice question on the second page?
Original post by Decoder
oh what did people get for the steam multiple choice question on the second page?

the work done is 0J
Reply 64
Wait how did you get 0
Original post by Decoder
Wait how did you get 0

work done in a couple = 0

you can google this or derive it
Doesn't the velocity increase as when a ball falls towards the ground it generally speeds up. The graph was a displacement time graph. Then it said air resistance was negligible which would mean the ball would accelerate constantly at 9.81ms^-2 so velocity would increase as it's accelerating? Thank you for all your answers btw, they're very helpful :smile:
Original post by thekidwhogames
velocity is decreasing as the gradient is getting more negative but magnitude of velocity increasing and it comes to instanreous rest then rebounds (so vpositive velocity but negative gradient e.g. negative acceleration)
Original post by thekidwhogames
work done in a couple = 0

you can google this or derive it


I thought that since the question asked about the rotation work done, so it couldn't be 0 since it said it rotated once. Idk if i'm remembering this question correctly. so I did circumference x force x 2?
Original post by MrsFredWeasley
Doesn't the velocity increase as when a ball falls towards the ground it generally speeds up. The graph was a displacement time graph. Then it said air resistance was negligible which would mean the ball would accelerate constantly at 9.81ms^-2 so velocity would increase as it's accelerating? Thank you for all your answers btw, they're very helpful :smile:


Velocity decreases as gradient was negative and displacement is negative but the magnitude of velocity was increasing E. G. Speed
Original post by Toednote3363
I thought that since the question asked about the rotation work done, so it couldn't be 0 since it said it rotated once. Idk if i'm remembering this question correctly. so I did circumference x force x 2?


It asked for work done by couple I think
Reply 70
u say it was easy but half your answers are wrong
Original post by thekidwhogames
It was quite easy

Power dissipated ratio is 0.334 or somerhing
Current 0.76I
Work done multiple choice is 0
Path difference is the one which diff is a multiple of 10

Force 260N
Original post by ItsEuan
u say it was easy but half your answers are wrong


How was it wrong lol I'll explain all of them
Power in internal resistance do i^2 x r so 0.76 x 0. 62^2

Power supplied by cell do iv so 0. 76 x 1. 4

Divisd them u get 0. 34 to 2sf
To find current do parallel then series resistance and find total current
For force is 260

Do change in momentum over time

V is 3.5
U is - 4.9

So 56/1000 * (3.5--4.9) then divide by time which was 1.8*10^-3 so u get 260N to 2sf
To make it constructive path diff is a multiple of 10 so it'd the 75 and 95 obe

For q20 it was closed and open so starts with node and ends with anti node so c

Work done in a couple is 0

Power saved was just calculating to be 144£

The x3 one is 0.36 and 1 and u use kirchoff and work it out
The ratio of x

Well Yb=1.29Ya which was given

Yb=FbLb/AbXb
Ya=FaLa/AaXb

A and l are same so cancel

Fb/Xb=1.29Fa/Xb

Forces were tension so now rearrange for Xb/xa giving 0.996 to 3sf
For practical and explaining they're in the book

Gradient have half of V as V=F lamda

Lamda = 2 x distance
But gradient gives distance x f which is half of it obviously
Anything wrong with these?
Reply 79
What do you guys think the grade boundaries will be? From E to A?

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