Okay that's what I meant I just forgot
I think I lost a mark finding the area of triangle ABC but it was only 2 marks and I did the method right
Overall feeling pretty happy

Original post by BeastHassan

I got 8/9

Reply 11

Yolotwice

6

I think that's what I got

Original post by BeastHassan

I got 8/9

Reply 12

BeastHassan

1

For the triangle area I got 6 units ^2

Original post by dumbasslmao

Okay that's what I meant I just forgot
I think I lost a mark finding the area of triangle ABC but it was only 2 marks and I did the method right
Overall feeling pretty happy

Reply 13

Yolotwice

6

What was t?

Original post by dumbasslmao

Okay that's what I meant I just forgot
I think I lost a mark finding the area of triangle ABC but it was only 2 marks and I did the method right
Overall feeling pretty happy

Reply 14

dumbasslmao

8

t= 7/4

And triangle area was 39/8 I think but I don't even know if I put that down

Reply 15

Yolotwice

6

It was a bottom heavy fraction over 9 defo not 2

Reply 16

revsvk

2

Original post by sadiqimusa

i messed up on these questions

op

what paper is this oh my god

Reply 17

daveGpufc

1

The inequality/discriminant Q..
Pretty sure
a= 1
b= 6k-10
c= 2k-3
They said they cross at 2 distinct points and wanted to show the final inequality was GREATER than zero, but the inequality of that ^ discriminant ended up exactly the same as they had wanted you to show but BELOW zero as two distinct points of intersection? There was no multiplying by a negative to switch the signs as it already simplified to what they had shown with the correct signs. Did anyone else have this problem or did I just miss something?

Reply 18

Yolotwice

6

Wrong paper

Original post by daveGpufc

The inequality/discriminant Q..
Pretty sure
a= 1
b= 6k-10
c= 2k-3
They said they cross at 2 distinct points and wanted to show the final inequality was GREATER than zero, but the inequality of that ^ discriminant ended up exactly the same as they had wanted you to show but BELOW zero as two distinct points of intersection? There was no multiplying by a negative to switch the signs as it already simplified to what they had shown with the correct signs. Did anyone else have this problem or did I just miss something?