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Edexcel IAL Physics unit 2 (Old Syllabus) WPH02 May 2019

usman200186

Hello everyone, this thread is For physics old syllabus. The exam is on 17 may. Feel free to discuss your problems and ask questions here.

January 2019 Papers can be found here: https://m.facebook.com/notes/edumaestro/edexcel-exam-materials-all-qualifications-gcse-igcse-gce-ial/236083640431373

For unit 2 notes, you can use physicsmathstutor.com

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Hellooo!

Original post by ree.x09

Hellooo!

Reply 3

ree.x09

Do you have any revision note containing a list of all the definitions required for unit 2?

Reply 4

ree.x09

Will solving papers from 2019jan to 2015 be enough?

Reply 5

usman200186

Original post by ree.x09

Will solving papers from 2019jan to 2015 be enough?

Yeah I think its enough. Go to physics maths tutor and they have flashcards for definitions. Most of the definitions are from electricity

Reply 6

ree.x09

Original post by usman200186

Yeah I think its enough. Go to physics maths tutor and they have flashcards for definitions. Most of the definitions are from electricity

Thanks a lot. You’re really helpful!

Reply 7

usman200186

How do we find radiation flux? I cannot ffind any formula in my book.....
And what about the 2nd part? We divide 4590J by 110J IMG_20190516_044655-compressed.jpg.jpeg

Reply 8

usman200186

And I have another question, why is it beneficial to use potential divider in a circuit?

Reply 9

mechguffin

Original post by usman200186

How do we find radiation flux? I cannot ffind any formula in my book.....
And what about the 2nd part? We divide 4590J by 110J IMG_20190516_044655-compressed.jpg.jpeg

The first part is easy. You're told to find Radiation Flux (A.K.A Intensity) and Intensity = Power / Area (Check the back of your book if you're using the Miles Hudson one)
Since you're given energy, you can use, Power = Energy / Time and find intensity afterwards (P.S. Time is 1 hours so 60²seconds)

2nd part states that, you need to find the efficiency which is, (Useful Energy Output / Total Energy Input) x 100 ---> Here that'd be, (110 J / 4590 J) * 100 = 2.4%

Original post by usman200186

And I have another question, why is it beneficial to use potential divider in a circuit?

I've also found these 2 links:

(1) https://en.wikipedia.org/wiki/Voltage_divider
(2) https://www.quora.com/What-are-the-advantages-of-voltage-divider

Let me know where you found the potential divider question so I could see the mark scheme and compare my answers. Cheers!

Reply 10

usman200186

Original post by mechguffin

Thank you soo much for explaining all this cu i was a bit confused in intensity and radiation flux, but they are just the same thing. this past paper is january (IAL) 2017

Reply 11

ree.x09

Yeah i don’t understand the potential divider questions at all. What does a potential divider do? Can someone please explain in short? Or links to any videos?

Reply 12

usman200186

Original post by ree.x09

Yeah i don’t understand the potential divider questions at all. What does a potential divider do? Can someone please explain in short? Or links to any videos?

Same, my concept is that potential divider changes the voltage in circuit like it can control the circuit. Cuz if you change voltage, the current changes so does resistance.

Reply 13

ree.x09

Can someone please explain me how 13(c) is done. Which formula they using?

Attachment not found

Here’s the markscheme

Attachment not found

(edited 4 years ago)

A325E4DB-1EBF-4590-8895-A11D42BACA73.jpg.jpeg11.6KB

E200F59C-47FB-4350-BB30-E1C7AC8A2790.jpg.jpeg51.3KB

Reply 14

686868t

Original post by usman200186

And I have another question, why is it beneficial to use potential divider in a circuit?

You can reduce the p.d to 0
It does not affect the current

Reply 15

686868t

Original post by ree.x09

Can someone please explain me how 13(c) is done. Which formula they using?

Attachment not found

Here’s the markscheme

Attachment not found

13 c) u use the equation hf=work function +K.E
the mass in KE will be the mass of an electron (found in ur data booklet) andddd thats it?

Reply 16

686868t

Original post by usman200186

Same, my concept is that potential divider changes the voltage in circuit like it can control the circuit. Cuz if you change voltage, the current changes so does resistance.

same here, spent all of yesterday finding anything to explain it but basically it doesnt affect the current
so rheostats (variable resistors) alter the current
Potential dividers alters the voltage
just remember that i guess😂