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Avogadro constant help please

How many protons are there in 6.0g of nitrogen gas?
Avogadro constant = 6.022 x 10^23 mol-1

Answer is 1.8 x 10^24
How do I get to this?
Reply 1
Original post by anactualmess
How many protons are there in 6.0g of nitrogen gas?
Avogadro constant = 6.022 x 10^23 mol-1

Answer is 1.8 x 10^24
How do I get to this?


How many protons are there per molecule of N2?
14?
Original post by Pigster
How many protons are there per molecule of N2?
Reply 3
Original post by anactualmess
14?

how many molecules of gas in 6g?
well there's 6.022 x 10^23 molecules of gas in 28g
28/6 = 4.7
so assuming you divide 6.022 x 10^23 by 4.7 to get the number of molecules of gas in 6g? So 1.3 x 10^23?
Original post by sotor
how many molecules of gas in 6g?
Reply 5
Original post by anactualmess
well there's 6.022 x 10^23 molecules of gas in 28g
28/6 = 4.7
so assuming you divide 6.022 x 10^23 by 4.7 to get the number of molecules of gas in 6g? So 1.3 x 10^23?

yep! be careful of rounding errors, you should have 1.29*10^23.
I did (6/28)*(6.02*10^23) but if your way makes sense to you then stick with that

so how many protons in 1.3*10^23?
only thing I can think of is 1.29 x 10^23 x 14? But I don't really understand why that is
Original post by sotor
yep! be careful of rounding errors, you should have 1.29*10^23.
I did (6/28)*(6.02*10^23) but if your way makes sense to you then stick with that

so how many protons in 1.3*10^23?
Reply 7
Original post by anactualmess
only thing I can think of is 1.29 x 10^23 x 14? But I don't really understand why that is

yep! if you have 14 protons in every molecule, then in 100 molecules you have 100x14 protons

and if you have 1.29*10^23 molecules, you get your answer

does that make sense?
ah okay thank you!
Original post by sotor
yep! if you have 14 protons in every molecule, then in 100 molecules you have 100x14 protons

and if you have 1.29*10^23 molecules, you get your answer

does that make sense?
Reply 9
first find the number of moles Mr(N2) = 14X2 = 28mass = 6.0gn(mol)= mass/Mr = 6/28 =Ans number of 1 proton = 6.022x10^23 x Ans = Ans2Nitrogen(N) has 7 protons where as N2 would have x2 = 14total protons in N2 gas 14 x Ans 2
1.) Work out moles of Nitrogen : 6g/14 = 0.42892.) Workout the number of particles by multiplying the moles by Avogadro's constant : 0.04289 x 6.022x10^23 = 2.58 x10^23.3.) Because there are 7 protons in each particle of N, multiply your anwser by 7 which give syou 1.8 x10^24.
Original post by ZzZzZz121212
1.) Work out moles of Nitrogen : 6g/14 = 0.42892.) Workout the number of particles by multiplying the moles by Avogadro's constant : 0.04289 x 6.022x10^23 = 2.58 x10^23.3.) Because there are 7 protons in each particle of N, multiply your anwser by 7 which give syou 1.8 x10^24.

Wouldn’t you multiply by 14 because it’s N2 so (7+7) = 14 protons
Original post by Jaafar123
Wouldn’t you multiply by 14 because it’s N2 so (7+7) = 14 protons

they worked out the moles of one atom of nitrogen so they did the protons per atom. I suggest doing it the other guy's way where you take into account it's diatomic and that you multiply it by 14 in the end
Reply 13
Original post by sotor
yep! if you have 14 protons in every molecule, then in 100 molecules you have 100x14 protons

and if you have 1.29*10^23 molecules, you get your answer

does that make sense?

Wrong!

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