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Edexcel A-level Further Decision 1 - 24th June 2019 [Exam Discussion]

Edexcel A level Further Decision 1

Here is the exam discussion for this exam. Talk anything from how to revise for it, specific questions or time management :ahee:
Date: 24th June
AM/PM:AM
Length:1h30
Specification:https://qualifications.pearson.com/content/dam/pdf/A%20Level/Mathematics/2017/specification-and-sample-assesment/a-level-l3-further-mathematics-specification.pdf

Other Resources:
Formula Booklet: https://qualifications.pearson.com/content/dam/pdf/A%20Level/Mathematics/2017/specification-and-sample-assesment/Pearson_Edexcel_A_Level_GCE_in_Mathematics_Formulae_Book.pdf
Sample Assessment Materials: https://qualifications.pearson.com/content/dam/pdf/A%20Level/Mathematics/2017/specification-and-sample-assesment/a-level-l3-further-mathematics-sams.pdf
Maths Study Group (including many resources): https://www.thestudentroom.co.uk/showthread.php?t=5747896
How to revise for the new specification: https://www.thestudentroom.co.uk/a-level/exams/how-to-revise-a-level-maths-new-spec
Maths Exam Thread Directory: To be added

:goodluck: with revision and exams :work:

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Reply 2
How's everyone revising d1?
Reply 3
Are these for the new spec?? could be useful https://www.examsolutions.net/solomon-d1-papers-edexcel/
Reply 4
Mainly textbook questions and the SAMs, Specimen material and the 2018 AS exam. Old D1 papers seem to be helpful as well. Wbu?
Original post by Clark1111
How's everyone revising d1?
Reply 5
Pretty much the same tbh and the 5 practice papers
Original post by AT2001
Mainly textbook questions and the SAMs, Specimen material and the 2018 AS exam. Old D1 papers seem to be helpful as well. Wbu?
Does anyone have any ideas about this?
https://www.thestudentroom.co.uk/showthread.php?t=6009052
I heard it was reccomended to use pencil in the old spec for filling out tables but I can't verify it or know if it will apply for this year as well.
Reply 7
I'm going to use a pen - better safe than sorry. Although I'll be bringing in a pencil and a highlighter so that I can annotate onto the question book. You are usually allowed to use pencil for diagrams/ sketches so I don't know if templates count as this.
Reply 8
any useful videos/guides for simplex 2 stage, travelling salesman and floyds?
Just did a practice mock and managed to bag 70/75 marks (couple silly mistakes with a linear programming constraint and a reasoning question). I might just not revise until Sunday night and chill for the next few days :woo:
Can you link the mock paper you have done, I would appreciate it very much :smile:

Thanks in advance and good luck!!
Original post by mohamadjamil03
Just did a practice mock and managed to bag 70/75 marks (couple silly mistakes with a linear programming constraint and a reasoning question). I might just not revise until Sunday night and chill for the next few days :woo:
Ah thanks! I didn't think to simply go to the homepage and find it myself
Reply 14
guys, how does one find the order of an algorithm?\#
Anyone else just ran out of steam at this point? Pretty tempted to just pack it up and wing it on the day, such a terrible module to revise for with the diagrams to draw and stuff
I have a question which is going to sound silly but I seem to always struggle with this:

If I have an objective line: y= -3/4 x +3 and it represents profit which I am wishing to maximise how do I convert it into a form of P +/- Ax +/- By = 0

Thanks in advance!!
you take y and x to one side
y+3/4 x=3
then times by 4
4y+3x=12
therefore P=4y+3x
Original post by AronAdamski
I have a question which is going to sound silly but I seem to always struggle with this:

If I have an objective line: y= -3/4 x +3 and it represents profit which I am wishing to maximise how do I convert it into a form of P +/- Ax +/- By = 0

Thanks in advance!!
Ah okay that does make sense, because the initial line I found is the objective function but not at its starting point, it would be starting at (0,0) and that's why its like this.

Thank you so much!
Original post by puneet12
you take y and x to one side
y+3/4 x=3
then times by 4
4y+3x=12
therefore P=4y+3x
Reply 19
Same man, just so late by this point
Original post by iFluffle
Anyone else just ran out of steam at this point? Pretty tempted to just pack it up and wing it on the day, such a terrible module to revise for with the diagrams to draw and stuff

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