Original post by Snowie9
How to solve an equation with same unknown but different power?
For example this:
12.17=0.036X + 1.9363x10^-8 X^3 -8.756x10^-9X^3 + 1.672x10^-12X^4
The answer is X=296.17
For example this:
12.17=0.036X + 1.9363x10^-8 X^3 -8.756x10^-9X^3 + 1.672x10^-12X^4
The answer is X=296.17
Use a computer.
If I can use a computer to solve it in my exams, I wouldn't be asking here for answers right?
Original post by RDKGames
Use a computer.
Original post by Snowie9
If I can use a computer to solve it in my exams, I wouldn't be asking here for answers right?
Can you use your calculator?
The analytical way is.... wasted effort, to say the least.
Numerical methods are your other option.
Isn't the highest degree is 3?
Original post by Snowie9
If I can use a computer to solve it in my exams, I wouldn't be asking here for answers right?
Original post by RDKGames
Can you use your calculator?
The analytical way is.... wasted effort, to say the least.
Numerical methods are your other option.
The analytical way is.... wasted effort, to say the least.
Numerical methods are your other option.
Original post by Snowie9
Isn't the highest degree is 3?
Last term has
Original post by Snowie9
No? There's a b c d in the 3 degree and I couldn't enter the term without unknown cause I can only enter 4 terms?
3rd degree polynomial means the highest power that occurs in the polynomial is .
You wrote yours as: 12.17=0.036X + 1.9363x10^-8 X^3 -8.756x10^-9X^3 + 1.672x10^-12X^4
The last term has X^4, which is the highest power of X in that equation, therefore the polynomial is a 4th degree one.
Original post by Snowie9
How to solve an equation with same unknown but different power?
For example this:
12.17=0.036X + 1.9363x10^-8 X^3 -8.756x10^-9X^3 + 1.672x10^-12X^4
The answer is X=296.17
For example this:
12.17=0.036X + 1.9363x10^-8 X^3 -8.756x10^-9X^3 + 1.672x10^-12X^4
The answer is X=296.17
couldn't you use the factor theorem and then algebraic long division?
Original post by chibichibi_xx
couldn't you use the factor theorem and then algebraic long division?
You've got a nested polynomial in the index with that last one? There is no way.
1.9636x10^2 * my bad. So I couldn't key into calculator cause there's 5 terms in the equation and calculator only allows 4
Original post by RDKGames
3rd degree polynomial means the highest power that occurs in the polynomial is .
You wrote yours as: 12.17=0.036X + 1.9363x10^-8 X^3 -8.756x10^-9X^3 + 1.672x10^-12X^4
The last term has X^4, which is the highest power of X in that equation, therefore the polynomial is a 4th degree one.
You wrote yours as: 12.17=0.036X + 1.9363x10^-8 X^3 -8.756x10^-9X^3 + 1.672x10^-12X^4
The last term has X^4, which is the highest power of X in that equation, therefore the polynomial is a 4th degree one.
Original post by Snowie9
1.9636x10^2 * my bad. So I couldn't key into calculator cause there's 5 terms in the equation and calculator only allows 4
Well I'm kinda lost on this thread at this stage. I even put your equation into Wolfram Alpha and X=296.17 is not a solution.
At this stage I recommend you figure out what went wrong, and where. Once you have the correct equation, check it on wolfram alpha to see that the given answer is indeed a solution, and then we can look at what options there are available for you as far as solving it goes.
https://www.wolframalpha.com/input/?i=12.17%3D0.036X+%2B+1.9363x10%5E-8+X%5E3+-8.756x10%5E-9X%5E3+%2B+1.672x10%5E-12X%5E4
Original post by Sinnoh
You've got a nested polynomial in the index with that last one? There is no way.
i don't think so.... it is supposed to look like
12.17=0.036X + 1.9363x10-8 X3 - 8.756x10-9X3 + 1.672x10-12X4
I get 327.20 and -6828.52?
Can you check your question again? Because I substituted your stated x value in the equation and I didn’t get zero. So, there must be something wrong with the question.
EDIT
(1.672×10−12×296.174)-(8.756×10−9×296.173)+(1.9363×10−8×296.173)+(0.036×296.17)-12.17 = -1.1391771.... ≉0
EDIT
(1.672×10−12×296.174)-(8.756×10−9×296.173)+(1.9363×10−8×296.173)+(0.036×296.17)-12.17 = -1.1391771.... ≉0
(edited 4 years ago)
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