Maths question help! Problem solving - NO CALC

Original post by Soohiiii

I am unsure of to achieve the answer for this? Any help...

NO CALCULATOR ALLOWED

What is the area of an equilateral triangle with a base of ‘x’.

All sides are x (equilateral).
So drop a perpendicular from the top to the base and the vertical height can be simply determined in terms of x, using the fact that the triangle is equilateral). Base is x.
Then its just
base*verticalHeight/2

Reply 2

Original post by Soohiiii

I am unsure of to achieve the answer for this? Any help...

NO CALCULATOR ALLOWED

What is the area of an equilateral triangle with a base of ‘x’.

The quickest way is to use Area = 1/2 ab sin(C). Since it's an equilateral triangle you should know what the angle (C) is.

Reply 3

I understand but I can’t seem to find one of the answer options

Original post by mqb2766

Reply 4

Original post by Soohiiii

I understand but I can’t seem to find one of the answer options

What do you think it is and what are the options?

Have you a value for x as you've edited post 1.

Reply 5

Original post by Sir Cumference

The quickest way is to use Area = 1/2 ab sin(C). Since it's an equilateral triangle you should know what the angle (C) is.

You can’t do this without a calculator though

Reply 6

Original post by Soohiiii

You can’t do this without a calculator though

You don't need one.
What is x, they must give you a value?

Reply 7

Original post by Soohiiii

You can’t do this without a calculator though

The sine value that you require is one of the ones that you would have learnt at GCSE - you’re expected to know it without using a calculator.

Reply 8

Original post by Soohiiii

Please post a picture of the question. It doesn’t make sense what you’ve posted here.

Reply 9

Original post by mqb2766

What do you think it is and what are the options?

Have you a value for x as you've edited post 1.

Original post by Sir Cumference

Please post a picture of the question. It doesn’t make sense what you’ve posted here.

I have attached a picture now

Reply 10

Original post by Sir Cumference

Please post a picture of the question. It doesn’t make sense what you’ve posted here.

There is now a picture

Reply 11

Original post by Soohiiii

There is now a picture

So how long is each side and what are the angles?

Reply 12

Original post by Soohiiii

So I'm guessing that the options you've posted here are incorrect and meant for another question?

Reply 13

Original post by Sir Cumference

So I'm guessing that the options you've posted here are incorrect and meant for another question?

They are the same as in the picture

Reply 14

Original post by mqb2766

So how long is each side and what are the angles?

It’s whatever is on the picture

Reply 15

Original post by Soohiiii

It’s whatever is on the picture

Ok, I'll drop out here.
You should try and put a bit of effort into answering these questions. They're meant to help you learn.

Reply 16

Original post by Soohiiii

They are the same as in the picture

No they're different. This is what you posted:

Options:
- (root 2)(6-(root 2))
- 6(4-(root 2))
- 6(root 2)
- 2(6-(root 2))
- (root 2)(4-(root 2))

Reply 17