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Vectors simple physics help please

You’re supposed to find this3ED13F6D-B5FF-4671-81EA-35778C2A9808.jpeg
Given this
DAB966D0-2084-415D-A6D2-467A2C24760C.jpeg
Here’s what I did, is my answer correct ?
7A7C2B8F-F620-43B5-B2C6-97AAC91401DA.jpeg
(edited 4 years ago)
Original post by Leah.J
You’re supposed to find this
Given this

Here’s what I did, is my answer correct ?

We need to see the question and your working to help you.
Reply 2
Original post by Muttley79
We need to see the question and your working to help you.

everything is uploaded now
Original post by Leah.J
everything is uploaded now

Was the diagram given to you? How does A = B or do you mean the magnitude is equal?
Reply 4
Original post by Muttley79
Was the diagram given to you? How does A = B or do you mean the magnitude is equal?

Only magnitude yes
Original post by Leah.J
Only magnitude yes

Sorry I really can't follow what you are trying to do here.
Reply 6
Original post by Muttley79
Sorry I really can't follow what you are trying to do here.

Find the magnitude of the 1st picture given in the info in the 2nd picture. This is exactly how we were given the question in the quiz.
The magnitude of A= that of B
There’s a 45 degree angle between them and A is parallel to the x axis.
Original post by Leah.J
Find the magnitude of the 1st picture given in the info in the 2nd picture. This is exactly how we were given the question in the quiz.
The magnitude of A= that of B
There’s a 45 degree angle between them and A is parallel to the x axis.


Your general method looks fine - pythagoras on the "x" and "y" components - except for the same error in each part:

(A+Acos45)2=???(A+A\cos 45)^2=???
(edited 4 years ago)
Reply 8
Original post by ghostwalker
Your general method looks fine - pythagoras on the "x" and "y" components - except for the same error in each part:

(A+Acos45)2=???(A+A\cos 45)^2=???

Oh , image.jpg ?
Original post by Leah.J
Oh , image.jpg ?


:party:

With that correction you should get the correct result, 1+21+\sqrt{2} or its decimal equivalent.
(edited 4 years ago)
Original post by Leah.J
...


Now that you have the result, an alternative method is to look at this geometrically. A diagram is often helpful with vectors.

I've not filled in all the details (left as an exercise), but refering to the diagram, the result you're looking for is tanx\tan x, where x is 67.5 degrees.

Untitled.jpg

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