# Further maths polynomials

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Thread starter 2 months ago
#1
When x^3+4x^2+kx+6 is divided by (x+5) the remainder is -4. What is k. I was doing polynomials today and got stuck on this question, what would I do to solve it? Would I use the factor/remainder theorem?
Thanks
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2 months ago
#2

hope this helps : )
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2 months ago
#3
(Original post by duckduck..goose)

hope this helps : )
whoops! thought the remainder was equal to 4. if its -4 then it should be -5k = 15, and k = -3.
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2 months ago
#4
(Original post by Noah00)
When x^3+4x^2+kx+6 is divided by (x+5) the remainder is -4. What is k. I was doing polynomials today and got stuck on this question, what would I do to solve it? Would I use the factor/remainder theorem?
Thanks
You'd have been better to post in the maths forum, rather than this umbrella forum which is no where near as heavily frequented.

In answer to your question, yes, the remainder theorem.

If we call your polynomial f(x), then you have f(-5) = -4. Just plug in the numbers and solve for k.
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2 months ago
#5
(Original post by duckduck..goose)
whoops! thought the remainder was equal to 4. if its -4 then it should be -5k = 15, and k = -3.
K is 3 not -3
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