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Senior moment... Average Gradient

Came across this question. Confused about why part a is worth 3 marks for a start. More to the point, what does it mean by "Average gradient"?
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Original post by dextrous63
Came across this question. Confused about why part a is worth 3 marks for a start. More to the point, what does it mean by "Average gradient"?


Sounds to me like finding the average value of a function f(x)f(x) over the domain [a,b][a,b] as 1b−a∫abf(x)dx\displaystyle \dfrac{1}{b-a} \int_a^b f(x) dx

Just in this case, it's f′f' which we are considering and only for the portion of motion concerning descent, i.e. from t=π2t=\dfrac{\pi}{2} to π\pi
(edited 4 years ago)
Original post by RDKGames
Sounds to me like finding the average value of a function f(x)f(x) over the domain [a,b][a,b] as 1b−a∫abf(x)dx\displaystyle \dfrac{1}{b-a} \int_a^b f(x) dx

Just in this case, it's f′f' which we are considering and only for the portion of motion concerning descent, i.e. from π2\dfrac{\pi}{2} to π\pi

...or it could just be the straight line gradient from the maximum point to the axis crossing to the right of it...
Reply 3
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T!gger34
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Thanks. I'll have a play with it later and get back to you.
Original post by dextrous63
Thanks. I'll have a play with it later and get back to you.


And the difference between the two suggestions is....
Reply 5
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T!gger34
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Original post by ghostwalker
And the difference between the two suggestions is....

None whatsoever. They yield the same correct answer. Thanks.
Original post by dextrous63
None whatsoever. They yield the same correct answer. Thanks.

:smile:
Reply 7
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T!gger34
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15
Original post by ghostwalker
:smile:

Still a mystery why part (a) is worth 3 marks.
Original post by dextrous63
Still a mystery why part (a) is worth 3 marks.


Aye - money for old rope, as they say.

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