I don't understand why the ones in A are identical and the ones in C aren't , I know that B are enantiomers because they're non-superimposable mirror images of each other but I don't know how to determine what A an C are
Rotate the second compound in A 120 degrees anticlockwise. Should be identical. Rotate the second compound in C 120 degrees clockwise. Should see an enantiomer.
If you're struggling to make sense of it, take a piece of a4 paper and roll it up to make a straw, repeat for a second piece. Twist one straw around the centre of the other and label the ends or colour code them to represent each molecule. You'll see as you rotate A in 3D space they're identical, it's just been rotated so the OH is facing away from you.
If you're struggling to make sense of it, take a piece of a4 paper and roll it up to make a straw, repeat for a second piece. Twist one straw around the centre of the other and label the ends or colour code them to represent each molecule. You'll see as you rotate A in 3D space they're identical, it's just been rotated so the OH is facing away from you.
can I ask another question ? Its a stupid one but I don't know how to decide whether an alkene has a chiral center or not, Why isn't the C on the left here considered a chiral center ? does it have to have 4 different groups attached to the double bond for their to be a chiral center ?
Yeah it has to has to be 4 different groups, as a general rule all alkenes are non-chiral with the exception of allenes.
They can still be stereoisomers though as they can't rotate about the double bond (with the exception of high temperature systems) and can't be superimposed.