I am not fully sure about the distances.
I said that the 5Kg was at the Centre of mass so thats how I got the 0.9m and then from that for both sides I did 0.9(5g). Is this the case or would you ignore the 5Kg because it is equal on both sides?
0.2m is the distance from B to C so that was the 0.2(2g)
If the vertical forces balance each other, the resolving forces vertically would give zero as they are equal.
If there’s no net turning effect the moments will be equal for P and Q?
I’m really sorry that I have made this confusing, I just started the topic today and in my notes I wasn’t given anything on Tensions.
Usually, when doing tensions, I would use F=ma where F is equal to the downwards mass- the tension in the string.
However, the topic was on moments so I assumed using moments equations was the way to go :/
Thanks,
Lucia