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I don't understand this question, can anyone pls helpπŸ˜πŸ˜‹

A team of 7 is chosen travels to a match in 2 cars. A group of 4 travel in one car and a group of 3 travel in the other car.
In how many different ways can the team of 7 be divided into a group of 4 and a group of 3?
(edited 3 years ago)
Reply 1
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vanessa_del
OP
6
Original post by theJoyfulGeek
So, you're choosing a group of 4 people from 7 people (and 3 are left over).
7C4, as order doesn't matter.

7C4 = 7!/4!3! = 7*6*5/3*2 = 35

So 35 ways of choosing the first 4, so a total of 35 ways.

(If you do 7C3, you also end up with 35).

So is the answer 35 πŸ˜ƒ
Reply 2
Avatar for vanessa_del
vanessa_del
OP
6
Original post by theJoyfulGeek
So, you're choosing a group of 4 people from 7 people (and 3 are left over).
7C4, as order doesn't matter.

7C4 = 7!/4!3! = 7*6*5/3*2 = 35

So 35 ways of choosing the first 4, so a total of 35 ways.

(If you do 7C3, you also end up with 35).

So is the answer 35 πŸ˜„
Reply 3
Avatar for vanessa_del
vanessa_del
OP
6
Original post by theJoyfulGeek
Yep! (Unless I've messed up somewhere due to my lack of calculator).

Thank you so much for the help πŸ˜‹

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