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partial fraction help

(a2x4a2b2x2+2ax+2b)/x2b2) (a^2x^4-a^2b^2x^2+2ax+2b)/x^2-b^2)
(edited 3 years ago)
Reply 1
Original post by mathsnotwhizz
(a2x4a2b2x2+2ax+2b)/x2b2) (a^2x^4-a^2b^2x^2+2ax+2b)/x^2-b^2)


You could split the numerator up into
(a^2x^4 - a^2b^2x^2) + (2ax + 2b)
And factorise and simplify the first expression, then do partial fractions on the second.

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