miarenn12
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Given that y=1/64x^3 express each of the following in the form kx^n, where k and n are constants.
a) y^1/3
b)4y^-1
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Plücker
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(Original post by miarenn12)
Given that y=1/64x^3 express each of the following in the form kx^n, where k and n are constants.
a) y^1/3
b)4y^-1
Is that \dfrac{1}{64x^3} or \dfrac{1}{64}x^3

How far have you got?

Post your working.
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miarenn12
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(Original post by Plücker)
Is that \dfrac{1}{64x^3} or \dfrac{1}{64}x^3

How far have you got?

Post your working.
The second, not very far. The answers are a) 1/4 x and b) 256x^-3
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mqb2766
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What is y^(-1)? Either treat it as
1/y
Or use the rules of indices. Then multiply by 4.
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stepsis9000
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I did some surds for my homework yesterday
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vix.xvi
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remeber for a, y^1/3 just means cube root
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