chemistry equilibrium help
Compounds A and B react together to form an equilibrium mixture containing compounds C and D according to the equation
2A + B ⇌ 3C + D
A beaker contained 40 cm3 of a 0.16 mol dm–3 aqueous solution of A.
9.5 × 10–3 mol of B and 2.8 × 10–2 mol of C were added to the beaker and the mixture was left to reach equilibrium.
The equilibrium mixture formed contained 3.9 × 10–3 mol of A.
Calculate the amounts, in moles, of B, C and D in the equilibrium mixture.
answer mark scheme:
Initial amount of A = 6.4 × 10–3
Equ A = 6.4 × 10–3 - 2x so x=1.25x10-3
this is the part im stuck on; why can't you divide 6.4x10-3 by 2 to get x?
2A + B ⇌ 3C + D
A beaker contained 40 cm3 of a 0.16 mol dm–3 aqueous solution of A.
9.5 × 10–3 mol of B and 2.8 × 10–2 mol of C were added to the beaker and the mixture was left to reach equilibrium.
The equilibrium mixture formed contained 3.9 × 10–3 mol of A.
Calculate the amounts, in moles, of B, C and D in the equilibrium mixture.
answer mark scheme:
Initial amount of A = 6.4 × 10–3
Equ A = 6.4 × 10–3 - 2x so x=1.25x10-3
this is the part im stuck on; why can't you divide 6.4x10-3 by 2 to get x?
Because
equilibrium A = initial A -2x
=> 2x = initial A -equilibrium A
=> 2x = 6.4x10^-3. - 3.9x10^-3
=> 2x= 2.5x10^-3
=>. x = 1.25x10^-3
You have to work out the number moles of A that have reacted. So initial number of moles takeaway moles that are left in equilibrium = 2x
equilibrium A = initial A -2x
=> 2x = initial A -equilibrium A
=> 2x = 6.4x10^-3. - 3.9x10^-3
=> 2x= 2.5x10^-3
=>. x = 1.25x10^-3
You have to work out the number moles of A that have reacted. So initial number of moles takeaway moles that are left in equilibrium = 2x
(edited 3 years ago)
Original post by GabiAbi84
Because
equilibrium A = initial A -2x
=> 2x = initial A -equilibrium A
=> 2x = 6.4x10^-3. - 3.9x10^-3
=> 2x= 2.5x10^-3
=>. x = 1.25x10^-3
You have to work out the number moles of A that have reacted. So initial number of moles takeaway moles that are left in equilibrium = 2x
equilibrium A = initial A -2x
=> 2x = initial A -equilibrium A
=> 2x = 6.4x10^-3. - 3.9x10^-3
=> 2x= 2.5x10^-3
=>. x = 1.25x10^-3
You have to work out the number moles of A that have reacted. So initial number of moles takeaway moles that are left in equilibrium = 2x
i dont understand why it's 2x
Original post by onedance1
i dont understand why it's 2x
From the formula you’re given the ratio of moles for each compound:
2A+B <=> 3C+D
So number of moles is x
2x of A + x of B <=> 3x of C + x of D
(I know those middle arrows aren’t the right sign, I don’t know how to type them on my phone)
Original post by GabiAbi84
From the formula you’re given the ratio of moles for each compound:
2A+B <=> 3C+D
So number of moles is x
2x of A + x of B <=> 3x of C + x of D
(I know those middle arrows aren’t the right sign, I don’t know how to type them on my phone)
2A+B <=> 3C+D
So number of moles is x
2x of A + x of B <=> 3x of C + x of D
(I know those middle arrows aren’t the right sign, I don’t know how to type them on my phone)
ohh i see, i just dont get why i cant divide the number of moles of A by 2 cause that's what i do for every other calculation
Original post by onedance1
ohh i see, i just dont get why i cant divide the number of moles of A by 2 cause that's what i do for every other calculation
You are but you have to work out how many moles of A have been used first.
So you work out the intial number of moles
Then the question gives you the number of moles remaining at equilibrium
So you take away the number of moles left at equilibrium from the initial number of moles to get how many moles actually reacted.
Then divide that number by two for the equation
(edited 3 years ago)
Quick Reply
Related discussions
- Confused about Kp and Kc - help please
- equilibriums in reversible reactions
- Chemistry Kc Question
- Kc question (hard?!)
- GCSE Chemistry Triple Science
- Advanced Higher Chemistry
- equilibrium chemistry
- chemistry as level equilibria help
- Hardest GCSE chemistry topic for you?
- Chemistry help please !!!
- what is the 5 marker (practical question) of ocr as chemistry 2023 was on
- [Chemistry] Equilibrium Question
- chemistry aqa a level help
- Chemistry - acids
- A level chem Kp question
- AQA GCSE Combined Science Paper 2 Higher Tier (8464/C/2H) -13th June 2023 [Exam Chat]
- Equilibria and entropy changes at boiling temperature
- Dynamic equilibrium A-level Chemistry Question
- Chemistry - haber process
- Chem equilibrium
Latest
Trending
Last reply 1 week ago
Im confused about this chemistry question, why does it form these productsTrending
Last reply 1 week ago
Im confused about this chemistry question, why does it form these products
