because it starts with V/IR triangle
thats
V
---
I*R
and the 'second derivative' equations are just variations on V=I*R, R=V/I, I=V/R
so Power = Vsquared divided by R, is a reasonable equation, if Volts goes up a bit (and resistance is static) then power will increase due the square of the voltage.
whilst Power = I(current)squared times resistance, if current goes up a bit & (and resistance is static) then power will increase due the square of the current,
but if you consider, as your question asked, what if resistance increases?, in most simple circuits, when the resistance increases the current decreases!
Everything in the V/IR triangle is stable at a particular time, if R increases, usually someone has changed the circuit (*)
Ohms law, where it applies, is your friend
(*) there are VDR voltage dependent resistors & temperature dependent resistors = thermometers, but you often aren't asked about these in Power questions. In fact all resistors are a little bit temperature dependent , they have a TCR, temperature coefficient of resistance, again not usually dealt with at this level. This was the basis of the BBC Engineering recruitment interview, show a simple circuit, get candidate to describe first level & approximations, then move into real world second & further derivatives, down to atomic properties of the electronic materials. Presumably they only need "talent" nowadays