A bag contains 12 beads 2 of the beads are blue, 1 of the beads are green, 3 of the beads are purple the rest are red Julia takes a bead at random what is the probability that this bed is purple or red is 3/4
A bag contains 12 beads 2 of the beads are blue, 1 of the beads are green, 3 of the beads are purple the rest are red Julia takes a bead at random what is the probability that this bed is purple or red is 3/4
A bag contains 12 beads 2 of the beads are blue, 1 of the beads are green, 3 of the beads are purple the rest are red Julia takes a bead at random what is the probability that this bed is purple or red is 3/4
Let's seperate the beads into their colours: 2 blue 1 green 3 purple There are 12 beads in total so you can figure out the number of red beads.
P.s. P(A or B) = P(A)+P(B) - this is the 'rule' you need to answer this q.
So we know that there is 6 coloured beads other than the red beads. We know that there is 12 beads in total. therefore: 12 - 6 = 6 red beads we also know there are 3 purple beads so probability of picking a red bead only: 6/12 probability of picking a purple bead only: 3/12
Now the question says: 'what is the probability that this bead is purple or red?' This means we must use the AND rule: P(A or B) = P(A)+P(B) what this means is that we just add the probabilities of one of the two events occurring