# Maths help

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I'm doing a practice paper and one of the questions is

Solve

6x - 5y = 110

7x + 10y = 30

Can someone give me the answer AND explain how they got it because I never understand these question and YouTube isn't helping.

Solve

6x - 5y = 110

7x + 10y = 30

Can someone give me the answer AND explain how they got it because I never understand these question and YouTube isn't helping.

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#2

(Original post by

I'm doing a practice paper and one of the questions is

Solve

6x - 5y = 110

7x 10y = 30

Can someone give me the answer AND explain how they got it because I never understand these question and YouTube isn't helping.

**yourstruly101**)I'm doing a practice paper and one of the questions is

Solve

6x - 5y = 110

7x 10y = 30

Can someone give me the answer AND explain how they got it because I never understand these question and YouTube isn't helping.

Last edited by GabiAbi84; 2 months ago

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(Original post by

First :Put the first equation into terms of y.

**GabiAbi84**)First :Put the first equation into terms of y.

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#4

(Original post by

First :Put the first equation into terms of y.

**GabiAbi84**)First :Put the first equation into terms of y.

(Original post by

Oh god, this just shows how bad I am at maths : (

**yourstruly101**)Oh god, this just shows how bad I am at maths : (

6x - 5y = 110

7x + 10y = 30

now I would multiply all of 6x - 5y = 110 by 2 then add the two equations together, the y's should cancel out and you can solve for x

then use your value for x and substitute it in to one of the equations to find y

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#6

multiply 6x-5y=110 by 2 to get 12x-10y=220. Now both equations have a y multiple that can cancel out. So you do (12x-10y=220) + (7x+10y=30). So -10y+10y=0 so we can remove that leaving us with. (12x+7x)=(220+30). This is 19x=250. Divide both sides by 19 to get x=250/19. Substitute the x back in to any one of the original equations to get y. So 6(250/19)-5y=110. Expand the brackets to get (1500/19)-5y=110. Subtract both sides by 1500/19 to get -5y=590/19. Divide both sides by -5 to get y=-118/19. hope this helps

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(Original post by

why? it's simultaneous equations

so you have these

6x - 5y = 110

7x + 10y = 30

now I would multiply all of 6x - 5y = 110 by 2 then add the two equations together, the y's should cancel out and you can solve for x

then use your value for x and substitute it in to one of the equations to find y

**laurawatt**)why? it's simultaneous equations

so you have these

6x - 5y = 110

7x + 10y = 30

now I would multiply all of 6x - 5y = 110 by 2 then add the two equations together, the y's should cancel out and you can solve for x

then use your value for x and substitute it in to one of the equations to find y

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(Original post by

multiply 6x-5y=110 by 2 to get 12x-10y=220. Now both equations have a y multiple that can cancel out. So you do (12x-10y=220) + (7x+10y=30). So -10y+10y=0 so we can remove that leaving us with. (12x+7x)=(220+30). This is 19x=250. Divide both sides by 19 to get x=250/19. Substitute the x back in to any one of the original equations to get y. So 6(250/19)-5y=110. Expand the brackets to get (1500/19)-5y=110. Subtract both sides by 1500/19 to get -5y=590/19. Divide both sides by -5 to get y=-118/19. hope this helps

**mdbdidjdksnd**)multiply 6x-5y=110 by 2 to get 12x-10y=220. Now both equations have a y multiple that can cancel out. So you do (12x-10y=220) + (7x+10y=30). So -10y+10y=0 so we can remove that leaving us with. (12x+7x)=(220+30). This is 19x=250. Divide both sides by 19 to get x=250/19. Substitute the x back in to any one of the original equations to get y. So 6(250/19)-5y=110. Expand the brackets to get (1500/19)-5y=110. Subtract both sides by 1500/19 to get -5y=590/19. Divide both sides by -5 to get y=-118/19. hope this helps

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**mdbdidjdksnd**)

multiply 6x-5y=110 by 2 to get 12x-10y=220. Now both equations have a y multiple that can cancel out. So you do (12x-10y=220) + (7x+10y=30). So -10y+10y=0 so we can remove that leaving us with. (12x+7x)=(220+30). This is 19x=250. Divide both sides by 19 to get x=250/19. Substitute the x back in to any one of the original equations to get y. So 6(250/19)-5y=110. Expand the brackets to get (1500/19)-5y=110. Subtract both sides by 1500/19 to get -5y=590/19. Divide both sides by -5 to get y=-118/19. hope this helps

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#10

(Original post by

How did you get 19x = 250

**yourstruly101**)How did you get 19x = 250

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(Original post by

12x+7x is 19x. and 220+30 is 250. so the equation becomes 19x=250

**mdbdidjdksnd**)12x+7x is 19x. and 220+30 is 250. so the equation becomes 19x=250

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**mdbdidjdksnd**)

multiply 6x-5y=110 by 2 to get 12x-10y=220. Now both equations have a y multiple that can cancel out. So you do (12x-10y=220) + (7x+10y=30). So -10y+10y=0 so we can remove that leaving us with. (12x+7x)=(220+30). This is 19x=250. Divide both sides by 19 to get x=250/19. Substitute the x back in to any one of the original equations to get y. So 6(250/19)-5y=110. Expand the brackets to get (1500/19)-5y=110. Subtract both sides by 1500/19 to get -5y=590/19. Divide both sides by -5 to get y=-118/19. hope this helps

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#13

(Original post by

I'm asking too many questions sorry but when you said divide both sides by 19 to x would that be 0.38

**yourstruly101**)I'm asking too many questions sorry but when you said divide both sides by 19 to x would that be 0.38

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(Original post by

so 19x/19 is just 1x. and 250/19 is 13.157... which is a long decimal so it's better to just keep it as a fraction which is 250/19. so x=250/19

**mdbdidjdksnd**)so 19x/19 is just 1x. and 250/19 is 13.157... which is a long decimal so it's better to just keep it as a fraction which is 250/19. so x=250/19

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#15

(Original post by

why? it's simultaneous equations

**laurawatt**)why? it's simultaneous equations

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**mdbdidjdksnd**)

so 19x/19 is just 1x. and 250/19 is 13.157... which is a long decimal so it's better to just keep it as a fraction which is 250/19. so x=250/19

x= 10

y = 10

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#17

(Original post by

So I've done it and I've looked at the mark scheme to correct my work and the answer is

x= 10

y = 10

**yourstruly101**)So I've done it and I've looked at the mark scheme to correct my work and the answer is

x= 10

y = 10

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#18

**yourstruly101**)

So I've done it and I've looked at the mark scheme to correct my work and the answer is

x= 10

y = 10

Can you upload a picture of the question?

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(Original post by

Those values don't satisfy the equations you posted originally!

Can you upload a picture of the question?

**davros**)Those values don't satisfy the equations you posted originally!

Can you upload a picture of the question?

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