Mechanics- velocity and acceleration

Its question 11

it shows decelerating

the block is lifted from ground at a constant speed till 5s. after 5s it slips and decelerates at 10m/s^2 and reaches a height of 6m which means the total area under the graph is 6m

That's what the question says, does your graph show that?

Have a think for maybe 10 minutes and explicitly match the different sections to the question. There are a few important mistakes even though the graph is relatively simple. The more you can do yourself, the better you'll understand/remember. If you have a specific question about what something means, post

Have a think for maybe 10 minutes and explicitly match the different sections to the question. There are a few important mistakes even though the graph is relatively simple. The more you can do yourself, the better you'll understand/remember. If you have a specific question about what something means, post that.

Have a think for maybe 10 minutes and explicitly match the different sections to the question. There are a few important mistakes even though the graph is relatively simple. The more you can do yourself, the better you'll understand/remember. If you have a specific question about what something means, post th

Have a think for maybe 10 minutes and explicitly match the different sections to the question. There are a few important mistakes even though the graph is relatively simple. The more you can do yourself, the better you'll understand/remember. If you have a specific question about what something means, post that.

I got the ans using displacement and not the area under the graph. Can you pls tell me where am I going wrong in the graph part

Sure, can you upload your current attempt at the velocity-time graph? Maybe (briefly) mark on each section why you think it's that shape. I don't care whether the graph is right. I do care whether you try to explain your thinking behind the graph.