well I know this isn't right but what I originally did was say 41/50 was the common ratio and just put it into the sum to infinity = a/(1-r) where a=d and then I got 5 and 5/9 d so I did it wrong but not sure what Im meant to do as they dont give any other information
well I know this isn't right but what I originally did was say 41/50 was the common ratio and just put it into the sum to infinity = a/(1-r) where a=d and then I got 5 and 5/9 d so I did it wrong but not sure what Im meant to do as they dont give any other information
Think about it a bit more - you drop it from a certain height it bounces up and then goes back down - so you want total distance ...
d ------------ + 41d/50 + 41d/50 + ... initial drop + first up + first down + second up etc
Without working it out, I assume your initial common ratio for the bounce heights, of 41/50, is correct. You need to massage the sum slightly to get it into the form of a geometric progress plus/times a couple of bits.
Without working it out, I assume your initial common ratio for the bounce heights, of 41/50, is correct. You need to massage the sum slightly to get it into the form of a geometric progress plus/times a couple of bits.