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Maths

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Struggling on this, there’s no solutions for it too

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Reply 1
Original post by AllGrade999999
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Struggling on this, there’s no solutions for it too

e^2x = (u-1)^2
Which is the numerator. Should be straightforward to integrate wrt u?
Reply 2
Original post by mqb2766
e^2x = (u-1)^2
Which is the numerator. Should be straightforward to integrate wrt u?


Done - I get {integral} (u-1)^2 / u ?
Reply 3
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Reply 4
Original post by AllGrade999999
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The working is a bit wrong (cubic?), but the previous answer is right, so maybe a typo.
It's a quadratic numerator after cancelling by e^x.
Reply 5
Original post by mqb2766

The working is a bit wrong (cubic?), but the previous answer is right, so maybe a typo.
It's a quadratic numerator after cancelling by e^x.


I’m confused, so I was right?

e^3x is (u-1)^2

So I made everything in terms of u ,
Reply 6
Original post by AllGrade999999
I’m confused, so I was right?

e^3x is (u-1)^2

So I made everything in terms of u ,

No. Why do you think that?
Reply 7
Original post by mqb2766
No. Why do you think that?


I mean (u-1)^3*
Reply 8
Original post by AllGrade999999
I mean (u-1)^3*

Yes. It was slightly easier to cancel e^x first, then do the quadratic x->u substitution.
(edited 3 years ago)
Reply 9
Original post by mqb2766
Yes. It was slightly easier co cancel e^x first, then do the quadratic substitution.


u(u-1)^4 / u (u-1) ?
Original post by AllGrade999999
u(u-1)^4 / u (u-1) ?

I have no idea where you're going with this. You seem to be doing random algebra.
Just continue #3.
Reply 11
Original post by mqb2766
I have no idea where you're going with this.
Just continue #3.


🤣🤣🤣🤣🤣
Reply 12
Original post by mqb2766
I have no idea where you're going with this. You seem to be doing random algebra.
Just continue #3.


I’m confuzzeld😂😂

What quadratic??🤣
Original post by AllGrade999999
I’m confuzzeld😂😂

What quadratic??🤣

You must have understood how you got to post 3? Then simply integrate.
If not, describe what the problem is, I'm thoroughly confused what you're trying to do.
Reply 14
Original post by mqb2766
You must have understood how you got to post 3? Then simply integrate.
If not, describe what the problem is, I'm thoroughly confused what you're trying to do.


Ahhh! I seee it!!!
Reply 15
Original post by mqb2766
You must have understood how you got to post 3? Then simply integrate.
If not, describe what the problem is, I'm thoroughly confused what you're trying to do.


Oh my goodness, hold on pls
Original post by AllGrade999999
Oh my goodness, hold on pls

Can hardly wait ...
Reply 17
Original post by mqb2766
Can hardly wait ...


So it’s 1/u right?

I got {integral} 1/u + (u-1)^3 / (u-1) du
Original post by AllGrade999999
So it’s 1/u right?

I got {integral} 1/u + (u-1)^3 / (u-1) du

You really need to upload your working.
Reply 19
Original post by mqb2766
You really need to upload your working.


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