Hi all, First post... be gentle, lol. Old dog trying to learn new tricks....
I'm doing HNC/D Mech Engineering and I've come across this one that has me struggling a little.
One of your commonly-used laboratory instantaneous test signal voltages (vs) is
described by the equation…
Vs = 6sin(2pift - (pi/4))
where f = 1MHz and t represents time.
Make time (t) the subject of this formula, and hence determine the first point in time when
the instantaneous signal voltage has a magnitude of +3V.
I've rearranged the formula thus t = asin(3/6)+(pi/4) / 2pi = 0.6486 (assuming Vs is the +3V. I'm not convinced about this, though)
Am I along the right lines? Any assistance would be greatly appreciated.