The Student Room Group

statistics

A construction company purchased concrete drill bits that have a lifespan that follows a
normal distribution with a mean of 75 hours and a standard deviation of 3 hours of use.
(i) Determine the percentage of the company’s drill bits that will have to be replaced
by or before 70 hours of use.
[3 marks]
(ii) Determine the percentage of the company’s drill bits that will have a lifespan
between 70 and 80 hours
Reply 1
(i) So the lifespan X has a normal distribution, X~N(75, 3^2). You want P(X <=70) .. can be done on calculator.
(ii) You want P(70 < X < 80), again can be done on the right calculator....
Reply 2
Original post by vc94
(i) So the lifespan X has a normal distribution, X~N(75, 3^2). You want P(X <=70) .. can be done on calculator.
(ii) You want P(70 < X < 80), again can be done on the right calculator....

how do you do this on a calculator
Reply 3
Does your calculator have statistical functions, like normal distribution?
Reply 4
Original post by vc94
Does your calculator have statistical functions, like normal distribution?

no
Reply 5
Original post by jan_ai
no

Have you learnt about standardising a normal distribution using Z= (X - mu)/sigma ?

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