A long wooden cylinder is placed into a liquid and it floats. The length of the cylinder below the liquid level is 15cm.
The pressure exerted by the liquid alone on the bottom of the cylinder is 1.9 x 10^3 Pa.
Calculate the density of the liquid.
Hi can someone please help me with this question, my working and thoughts are below!
i thought you could use the equation: pressure = height x density x g
so 1.9 x10^3 = 0.15 x density x 9.81, density thus = 1291. 19 = 1300 kgm^-3
or i thought you could use this way below:
FB = PA
PA = density x volume x g
1.9 x 10^3 x A = density x volume x 9.81
1.9 x 10^3 x pi x r^2 = density x pi x r^2 x 0.15 x 9.81
1.9 x 10^3 x pi = density x pi x 0.15 x 9.81
5969.026046 = density x 4.62285359
density =5969.026046/4.62285359
= 1291.199456 = 1291.2 = 1300 kgm^-3
is this correct?