I'm trying to part b of this question. I think I've found the vector BH in part A to be -60i + 70j but honestly I'm not entirely sure and I have no clue where to start for part B
Hihi, It might be worth checking your answer for part a! Then for the second part, I suggest drawing a sketch. Then you can use some knowledge of trigonometry to work out some angles (from B to H), and then the bearing. Remember the bearing is the angle relative to north, goes clockwise, and is 3 digits. For example, an angle of 87 degrees clockwise is 087. An angle of 93 degrees anticlockwise will be 267. Let me know how you get on!
Hihi, It might be worth checking your answer for part a! Then for the second part, I suggest drawing a sketch. Then you can use some knowledge of trigonometry to work out some angles (from B to H), and then the bearing. Remember the bearing is the angle relative to north, goes clockwise, and is 3 digits. For example, an angle of 87 degrees clockwise is 087. An angle of 93 degrees anticlockwise will be 267. Let me know how you get on!
tysm for this! I'm a bit confused though if my answer for A is incorrect - could you give me some guidance?
Yep! Let me know what you get for your bearing when you get it and we can see if we match
I've attached a photo of the diagram I'm using to make it easier to explain my working - Using the trig, I can find the θ angle, but what I'm actually trying to find is the ∝ angle because the bearing goes clockwise. So I used tanθ = opp / adj to find θ (tan^-1 (60 / 80) = 36.87). Then I subtracted this value from 360 to find the actual bearing. 360 - 36.87 = 323.13 ≈ 323. Is this correct?
I've attached a photo of the diagram I'm using to make it easier to explain my working - Using the trig, I can find the θ angle, but what I'm actually trying to find is the ∝ angle because the bearing goes clockwise. So I used tanθ = opp / adj to find θ (tan^-1 (60 / 80) = 36.87). Then I subtracted this value from 360 to find the actual bearing. 360 - 36.87 = 323.13 ≈ 323. Is this correct?
Absolutely perfect. Beautiful diagram and answer in perfect form