The Student Room Group

Vector question help A2

Hi,
In the question below i keep checking my working and can't find a mistake with my numbers so i'm assuming my method's flawed?
Thank you
F868BC38-EB1A-4695-A18B-76B7662DD289.jpeg
54317764-26BE-42D2-B282-664325F0F844.jpeg
(edited 2 years ago)
Reply 1
The 625 should be 25. The magnitude of a is 5, so a^2 = 25.
(edited 2 years ago)
Reply 2
Original post by mqb2766
The 625 should be 25. The magnitude of a is 5, so a^2 = 25

But the vectors i'm adding to give the resultant are forces, so i need to equal it to the magnitude of the force, not acceleration, don't I?
(Using f=ma)
If not then why would they give me the mass?
Reply 3
Yes, missed the mass part. Just skim read the acceleration.
What does the model solution give?
(edited 2 years ago)
Reply 4
Original post by mqb2766
Yes, missed the mass part. Just skim read the acceleration.
What does the model solution give?

There's not a worked solution but the MS just says -7/3 and -3
Reply 5
-3 gives a force of magnitude 5. I guess -7/3 does the same, so your soln is correct, they;ve probably calculated witen the force has magnitude 5.
Note the -3 solution corresponds to a 3 : 4:5 triangle.
(edited 2 years ago)
Reply 6
Original post by mqb2766
-3 gives a force of magnitude 5. I guess -7/3 does the same, so your soln is correct, they;ve probably calculated witen the force has magnitude 5.
Note the -3 solution corresponds to a 3:4:5 triangle.

Thank you :smile:
Reply 7
Original post by Rhys_M
Thank you :smile:

There's another question of the same type to which I also get a wrong answer VVVV
Do you think the book has a systematic error?
FEF06BD3-D229-4BEC-876D-21F823CB9AE5.png
Reply 8
Not sure what the solution is, but your +10 isnt correct.
Sub the book answer and your corrected answer into the F = .. expression and you should be able to work out which is correct?

Quick Reply

Latest