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Maths question

express 3x^2-18x+16 in the form a(x-b)^2+c

no idea!
Original post by lala5646
express 3x^2-18x+16 in the form a(x-b)^2+c

no idea!

Completed square form - are you studying GCSE?

If you haven't learned this then expand out the brackets and compare coefficients - post your working
Reply 2
Original post by Muttley79
Completed square form - are you studying GCSE?

If you haven't learned this then expand out the brackets and compare coefficients - post your working

so would it be 3(x^2-18x)+16
Original post by lala5646
so would it be 3(x^2-18x)+16

No - that's not the same -- if you are going to do it like this you need to take out a factor of 3 from 18 too

a(x-b)^2+c = what when expanded?
Reply 4
Original post by Muttley79
No - that's not the same -- if you are going to do it like this you need to take out a factor of 3 from 18 too

a(x-b)^2+c = what when expanded?

ah so would it be 3x(x - 6)+16
Start by just taking out the 3 from x^2-18x
So it is 3(x^2-6x)+16
Then complete the square
(edited 2 years ago)
Reply 6
how do u do that pls
Original post by lala5646
ah so would it be 3x(x - 6)+16

Just take out the factor of 3 - you need the other terms
Reply 8
i dont get it
16349983424031546764515176623874.jpg
This should explain the method
Reply 10
so would it be 3(x^2 - 2x) + 9
Here's my solution.
Original post by lala5646
so would it be 3(x^2 - 2x) + 9

Not quite,
16349993296009086860764556796318.jpg
Reply 14
love u all

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