Completing the square when the x² value is more than 1

How do i complete the square when the x² value is more than one? For example if it was 3x² + 2x - 1

I had a really bad teacher last year and I have mocks in like 3 weeks and I still don't get it so any help would be greatly appreciated. Thanks

Factorise the co-effecient of x^2 so that it becomes 1

so in this case it would be 3[x^2+2/3x-1/3]

Factorise the co-effecient of x^2 so that it becomes 1

so in this case it would be 3[x^2+2/3x-1/3]

This used to get me so much glad I wasn't the only one

Glad I'm not alone

Did you get an answer?

How would I solve the equation once I've completed the square?