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OP

Original post by scimus63

I am not sure about this but I had a go!

I called the abundance of Ti 46 just x

so

using the abundances given:

(46 x2) + (47 x2) + (48 x) + 49 x 1) / 5 + x = 47.8 5+ x is the sum of all the abundances

= 235 + 48x / 5 + x = 47.8

= 235 + 48x = 239 + 47.8x
x = 20 but this seems high when comapred to the other abundances, but then again the average mass is very close to 48

maybe I have made an arithmetic error!

so total abundances are just 2 = 2+ 20 + 1 = 25.

so % for 46 is just 2/20 x 100% = 10%

Scimus I honestly dont know what to say but you are honestly a legend thank you so much.

Edit: Sorry my account is being dumb and wont let me rep you

(edited 2 years ago)

Reply 5

Original post by English143

Hi, I honestly have no clue. I am stuck with turning the ratio into a percentage or fraction. I basically just need the first step. Thanks

Think of it in terms of maths only
You have four variables where two are the same ratio and one is half of those two. This can be seen as 2x+2x+x+y=1
Also 46(2x)+47(2x)+48y+49x=47.8

Solve by substitution

Reply 6

ashvinsingh

Original post by scimus63

I am not sure about this but I had a go!

I called the abundance of Ti 46 just x

so

using the abundances given:

(46 x2) + (47 x2) + (48 x) + 49 x 1) / 5 + x = 47.8 5+ x is the sum of all the abundances

= 235 + 48x / 5 + x = 47.8

= 235 + 48x = 239 + 47.8x
x = 20 but this seems high when comapred to the other abundances, but then again the average mass is very close to 48

maybe I have made an arithmetic error!

so total abundances are just 2 = 2+ 20 + 1 = 25.

so % for 46 is just 2/20 x 100% = 10%

You did it right

Reply 7

Ghost of math

Original post by scimus63

I am not sure about this but I had a go!

I called the abundance of Ti 46 just x

so

using the abundances given:

(46 x2) + (47 x2) + (48 x) + 49 x 1) / 5 + x = 47.8 5+ x is the sum of all the abundances

= 235 + 48x / 5 + x = 47.8

= 235 + 48x = 239 + 47.8x
x = 20 but this seems high when comapred to the other abundances, but then again the average mass is very close to 48

maybe I have made an arithmetic error!

so total abundances are just 2 = 2+ 20 + 1 = 25.

so % for 46 is just 2/20 x 100% = 10%

For your last line shouldn’t it be 2/25 x100 as you’re looking at the abundance relative to the complete sample

Reply 8

OP

Original post by Chi chi5

Think of it in terms of maths only
You have four variables where two are the same ratio and one is half of those two. This can be seen as 2x+2x+x+y=1
Also 46(2x)+47(2x)+48y+49x=47.8

Solve by substitution

Is the abundance of 46Ti 8%, as thats what I got

Reply 9

OP

Original post by ashvinsingh

You did it right

I think it may be 8%, as you add them up to 25 and then change the ratio to out of 100. You then should get 80:8:8:4.

Reply 10

Original post by English143

Is the abundance of 46Ti 8%, as thats what I got

Well done

Reply 11

ashvinsingh

Original post by The A.G

For your last line shouldn’t it be 2/25 x100 as you’re looking at the abundance relative to the complete sample

The mean of 46 47 and 49 Ti is 47. So 2Ti47: TI48 forms TI 47.8 so must be in ratio 4:1 so TI48 must be 0.5. 0.5/5 = 1/10 = 10%

Reply 12

Original post by scimus63

I am not sure about this but I had a go!

I called the abundance of Ti 46 just x

so

using the abundances given:

(46 x2) + (47 x2) + (48 x) + 49 x 1) / 5 + x = 47.8 5+ x is the sum of all the abundances

= 235 + 48x / 5 + x = 47.8

= 235 + 48x = 239 + 47.8x
x = 20 but this seems high when comapred to the other abundances, but then again the average mass is very close to 48

maybe I have made an arithmetic error!

so total abundances are just 2 = 2+ 20 + 1 = 25.

so % for 46 is just 2/20 x 100% = 10%

Should be 49x not 49 y, and 48y

Reply 13

OP

Original post by Chi chi5

Should be 49x not 49 y, and 48y

Did you get 8%?

Reply 14