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I need help with Integration question

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Reply 1
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mqb2766
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Original post by Matheen1
A758C0D0-0E0E-4FB6-9608-A81BAF1BB285.jpeg

As usual, what have you done?
It does help to upload your working in the OP.
Reply 2
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Matheen1
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Original post by mqb2766
As usual, what have you done?
It does help to upload your working in the OP.

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Reply 3
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mqb2766
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Original post by Matheen1
8F9BF284-A1A0-4DA6-9ABC-B8C37211FB7A.jpeg

Thats not quite what the question is asking.
Sketch the curve and the boundary of the integration problem and upload?
Reply 4
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Matheen1
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Original post by mqb2766
Thats not quite what the question is asking.
Sketch the curve and the boundary of the integration problem and upload?

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Reply 5
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mqb2766
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Which part are you working out?
Also note your previous working misses out the lower limit part at the end.
(edited 2 years ago)
Reply 6
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Matheen1
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I’m trying to find the enclosed area in the middle.
Reply 7
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mqb2766
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Original post by Matheen1
I’m trying to find the enclosed area in the middle.

Agreed, you've only done from x = 1/2 .. 2 though, you're missing a bit.
Also note that your working doesn't include the lower or upper(?) limit in the previous post. The area should not be negative.
(edited 2 years ago)
Reply 8
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Matheen1
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Original post by mqb2766
Agreed, you've only done from x = 1/2 .. 2 though, you're missing a bit.
Also note that your working doesn't include the lower or upper(?) limit in the previous post. The area should not be negative.

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Reply 9
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Matheen1
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Original post by Matheen1
4E54A9B5-1EEF-413D-9F16-85C87006EFBD.jpeg

I really don’t know what to do.
Original post by Matheen1
I really don’t know what to do.

3/2 looks about right for 1/2..2. So what about the bit from 0..1/2.
Id bet you do know how to get that area.
Reply 11
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Matheen1
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Original post by mqb2766
3/2 looks about right for 1/2..2. So what about the bit from 0..1/2.
Id bet you do know how to get that area.

Wait how did u get 0…1/2?
Original post by Matheen1
Wait how did u get 0…1/2?

You want to find the area enclosed by the axes, the curve and x=2 and y=4. Do a sketch, rather than desmos, and shade in the area youve already calculated. Which bit is missing?
Reply 13
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Matheen1
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Original post by mqb2766
You want to find the area enclosed by the axes, the curve and x=2 and y=4. Do a sketch, rather than desmos, and shade in the area youve already calculated. Which bit is missing?

Isn’t the part that is left meant to be 0…2 I just can’t get my head around why it is 0…1/2
41368D6B-D58A-4312-B1EA-122E86E401DE.jpeg64.9KB
Original post by Matheen1
Isn’t the part that is left meant to be 0…2 I just can’t get my head around why it is 0…1/2

Tbh, Id forget about desmos (its good, but just sketch it on your paper as you would do in an exam).
Shade the area youve calculated, noting the limits youve used.
(edited 2 years ago)
Reply 15
Avatar for bexxr
bexxr
7
Wouldn't this be the correct way to draw the graph (R = area)?

Screenshot 2022-01-21 132517.jpg

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