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    (Original post by Choppie)
    Thanks! Both of you are legends!
    No prob
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    (Original post by Choppie)
    Thanks! Both of you are legends!
    :angelblush: thanks ;(
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    (Original post by L'Evil Fish)
    :angelblush: thanks ;(
    So c2 integration trapezium rule
    Like in the textbook it will give you the equation so like y = 2x +3
    Lines between x=1 and x=2

    Use the trapezium rule with 4 strips

    I don't know how to find what each value of x would be
    Answer is below

    So x will be 0, 0.5, 1, 1.5, 2






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    should I sleep in tomorrow and feel totally refreshed for my M1 exam after lunch


    OR

    should I get up early and cram?

    What are you doing?
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    (Original post by Tplox)
    So c2 integration trapezium rule
    Like in the textbook it will give you the equation so like y = 2x +3
    Lines between x=1 and x=2

    Use the trapezium rule with 4 strips

    I don't know how to find what each value of x would be
    Answer is below

    So x will be 0, 0.5, 1, 1.5, 2






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    Okay so:

    \int_{a}^{b} f(x) and n = number of ordinates/"strips"


    To find the x values.

    (b-a)/(n-1)

    You mean five strips btw

    So say I said:

    \int_{1}^{2} f(x) with five strips...

    (2-1)/(5-1)

    = 1/4 = 0.25

    And you'd have

    1, 1.25, 1.5, 1.75 and 2.
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    (Original post by L'Evil Fish)
    O
    You mean five strips btw
    You sure?
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    (Original post by joostan)
    How about:
    Solve (for x)\ 6^x = 5 \times 9^x giving your answer in exact and most simplified form.
    Ok you got me 🙈
    I don't know...


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    If I want to teach myself some modules of A level maths, what resources would you recommend? I'm considering C1 - 4, M1 - wherever and some further modules.
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    (Original post by chickenonsteroids)
    If I want to teach myself some modules of A level maths, what resources would you recommend? I'm considering C1 - 4, M1 - wherever and some further modules.
    Examsolutions.
    MathsHelper.
    Any textbook.
    And the best till last . . .
    Spoiler:
    Show
    TSR
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    (Original post by joostan)
    You sure?
    No I cba editing

    **** yeah! No more art for ever!

    Finished my book!!! yeaaaaaaaaaah
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    (Original post by L'Evil Fish)
    Okay so:

    \int_{a}^{b} f(x) and n = number of ordinates/"strips"


    To find the x values.

    (b-a)/(n-1)

    You mean five strips btw

    So say I said:

    \int_{1}^{2} f(x) with five strips...

    (2-1)/(5-1)

    = 1/4 = 0.25

    And you'd have

    1, 1.25, 1.5, 1.75 and 2.

    My bad, I meant x=0. Not 1 sorry
    But thank you, I get it now


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    (Original post by Tplox)
    My bad, I meant x=0. Not 1 sorry
    But thank you, I get it now


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    good!

    Try this then...

    \int_{1}^{3} ln(x) + 3 6 ordinates.

    Just the x coordinates.
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    (Original post by L'Evil Fish)
    No I cba editing

    **** yeah! No more art for ever!

    Finished my book!!! yeaaaaaaaaaah
    Lazy
    And . . .
    Spoiler:
    Show
    congrats:woo:
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    (Original post by joostan)
    Lazy
    And . . .
    Spoiler:
    Show
    congrats:woo:
    :yy:

    Aaah... 41 pages in my art book done :mmm: did my final piece... I'm done... Lets see what I get :mmm:
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    (Original post by chickenonsteroids)
    If I want to teach myself some modules of A level maths, what resources would you recommend? I'm considering C1 - 4, M1 - wherever and some further modules.
    www.examsolutions.net/

    http://www.m4ths.com/‎
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    (Original post by joostan)
    Examsolutions.
    MathsHelper.
    Any textbook.
    And the best till last . . .
    Spoiler:
    Show
    TSR

    Many thanks
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    I am currently doing this question: the 20th term in a arithmetic sequence is -7 & the sum of the first 20 terms is 430.
    How do i find 'a' & 'd'
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    (Original post by annaridgway95)
    .
    How about:
    Spoiler:
    Show
     6^x = 5 \times 9^x

\Rightarrow xlog_36 = log_35 + 2x 

\Rightarrow x(1 + log_32) - 2x = log_3 5

\Rightarrow x(log_32 - 1) = log_35

\Rightarrow x = \dfrac{log_35}{log_32 -1}
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    (Original post by Shegameister)
    I am currently doing this question: the 20th term in a arithmetic sequence is -7 & the sum of the first 20 terms is 430.
    How do i find 'a' & 'd'
    a + 19d = -7
    (20/2)(a+19d) = 430

    Are you sure that's right?
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    (Original post by L'Evil Fish)
    good!

    Try this then...

    \int_{1}^{3} ln(x) + 3 6 ordinates.

    Just the x coordinates.
    1, 1 1/3, 1 2/3, 2, 2 1/3, 2 2/3, 3


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