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    (Original post by tadit)
    For the circle equation question, how were the two possible values for k found? I subbed in the coordinates of P(4,k) into the circle equation (x+1)^2+(y-3)^2=50 and got a quadratic like x^2-6x-24=0 which I had to use the quadratic equation to get something like 3 plus or minus root 33... it seems some people got 8 or -2 or something
    So the question said x = 4 and y = k

    That turns into

    (k - 3)^2 = 25

    then

    k = 3 + 5 and 3 - 5

    so yeah -2 or 8
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    Anyone remember the values they got for k (for the circle question)? it's the only question I'm unsure about..
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    (Original post by Rajina.0)
    YES THATS WHAT I GOT TOO!
    That cylinder question was disgusting.
    It wasn't that hard if you knew the area and surface area of a cylinder.
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    (Original post by Heffalump .)
    the first bit was 108/5, not 163/5.. the final answer was 162/5
    yeah, that's what i meant, sorry
    I got 107/5 for the first bit
    and the. 54-107/5 = 163/5 for the second bit

    i messed up in some arithmetic in the first part of the question and it followed through - would i be penalised twice? how many marks would i lose in total?
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    i got k = -2 and 8 as well
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    (Original post by asunny1998)
    How did everyone find the paper?
    On the desk like everyone else
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    Can you explain 5.c) ? (It's really bugging me)
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    Anyone have any idea was 100UMS is going to be for this?
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    (Original post by DexterMabel123)
    i got 21.6 for the integration question anyone get this?
    I did!! It was that or 21.4 😆
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    (Original post by Programming_Nerd)
    So the question said x = 4 and y = k

    That turns into

    (k - 3)^2 = 25

    then

    k = 3 + 5 and 3 - 5

    so yeah -2 or 8
    How many marks was this worth?
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    (Original post by tanyapotter)
    yeah, that's what i meant, sorry
    I got 107/5 for the first bit
    and the. 54-107/5 = 163/5 for the second bit

    i messed up in some arithmetic in the first part of the question and it followed through - would i be penalised twice? how many marks would i lose in total?
    I messed up too, by using 98/5 instead of 108/5. I'm sure there will be method marks/follow through, but we will lose accuracy marks.


    (Original post by Hexaneandheels)
    Anyone have any idea was 100UMS is going to be for this?
    Probably 73-75
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    I looked there too, couldn't find anything
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    I got y = -4 and x = 9 :/
    (Original post by Hibzish)
    I tried the simultaneous equation so many times i got y=300 or sumthing it was the hardest paper i ever sat

    Posted from TSR Mobile
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    (Original post by Programming_Nerd)
    So the question said x = 4 and y = k

    That turns into

    (k - 3)^2 = 25

    then

    k = 3 + 5 and 3 - 5

    so yeah -2 or 8
    Oh I did 34-50=-24 but its -16... clever me. cheers though
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    (Original post by tanyapotter)
    yeah, that's what i meant, sorry
    I got 107/5 for the first bit
    and the. 54-107/5 = 163/5 for the second bit

    i messed up in some arithmetic in the first part of the question and it followed through - would i be penalised twice? how many marks would i lose in total?
    You would only lose one, as it's an error carried forward
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    Hopefully got 100 UMS, the cylinder question really wasn't that bad. If you didn't know the equation you could have used some common sense and seen that the circumference of a circle is 2πr and so you then times that by the height to get the surface area so it is 2πrh.

    Obviously then you can do what other people have said and do 48π = 2πrh + πr^2
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    (Original post by Heffalump .)
    How many marks was this worth?
    I think it was 3
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    I got 112/5. 108/5 was only the integrated bit. You had to take it away from the trapezium
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    (Original post by Heffalump .)
    Are you sure it was -9/4.. I thought it was -4/9..
    Yeah you're right I put that on the paper but copied it wrong!
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    (Original post by RhysKirkwood)
    You would only lose one, as it's an error carried forward
    really? omg that's great. thank you!
 
 
 
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